Part A - Isolating a VariableIsolating a variable in two equations is easiest when one of them has a coefficient of 1. Let's say we have the two equations3A - B=52A + 3B = -4●●and want to isolate one of the variables, such that it appears by itself on one side of the equation. Which of the following is an equation with one of the above variables isolated?► View Available Hint(s)2A-3B-4B = 3A-53B-2A-4B = 5-3ASubmitPrevious AnswersCorrectPart B - SubstitutionNow that we have one of the variables from Part A isolated, and written in terms of the other variable, we can now substitute this into the other of the two original equations. Which of the followingoptions represents this?3A (3A-5) = −42A +3(-5) = -42(B+5) +3B = −42A + 3(3A — 5) = −4- Part C - Solving for the VariablesWe now have an algebraic expression with only one variable, which can be solved. Once we have that, we can plug it back into one of the original equations (or the expression derived in Part A) tosolve for the other variable. When this is done with the system of two equations from Parts A and B, what is the solution?Enter A, then B, as two numbers, separated by a comma.View Available Hint(s)A, B =VO ΠΙ ΑΣΦ?

Part C- Solving for the Variables We now have an algebraic expression with only one variable, which can be solved. Once we have that, we can plug it back into one of the original equations (or the expression derived in Part A) solve for the other variable. When this is done with the system of two equations from Parts A and B, what is the solution? Enter A, then B, as two numbers, separated by a comma. ► View Available Hint(s) A, B = [5] ΑΣΦ ?

Part C- Solving for the Variables We now have an algebraic expression with only one variable, which can be solved. Once we have that, we can plug it back into one of the original equations (or the expression derived in Part A) solve for the other variable. When this is done with the system of two equations from Parts A and B, what is the solution? Enter A, then B, as two numbers, separated by a comma. ► View Available Hint(s) A, B = [5] ΑΣΦ ?

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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Question

Part A - Isolating a Variable
Isolating a variable in two equations is easiest when one of them has a coefficient of 1. Let's say we have the two equations
3A - B=5
2A + 3B = -4
●
●
and want to isolate one of the variables, such that it appears by itself on one side of the equation. Which of the following is an equation with one of the above variables isolated?
► View Available Hint(s)
2A-3B-4
B = 3A-5
3B-2A-4
B = 5-3A
Submit
Previous Answers
Correct
Part B - Substitution
Now that we have one of the variables from Part A isolated, and written in terms of the other variable, we can now substitute this into the other of the two original equations. Which of the following
options represents this?
3A (3A-5) = −4
2A +3(-5) = -4
2(B+5) +3B = −4
2A + 3(3A — 5) = −4
-

Part C - Solving for the Variables
We now have an algebraic expression with only one variable, which can be solved. Once we have that, we can plug it back into one of the original equations (or the expression derived in Part A) to
solve for the other variable. When this is done with the system of two equations from Parts A and B, what is the solution?
Enter A, then B, as two numbers, separated by a comma.
View Available Hint(s)
A, B =
VO ΠΙ ΑΣΦ
?

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