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Part C- Solving for the Variables We now have an algebraic expression with only one variable, which can be solved. Once we have that, we can plug it back into one of the original equations (or the expression derived in Part A) solve for the other variable. When this is done with the system of two equations from Parts A and B, what is the solution? Enter A, then B, as two numbers, separated by a comma. ► View Available Hint(s) A, B = [5] ΑΣΦ ?

Part C- Solving for the Variables We now have an algebraic expression with only one variable, which can be solved. Once we have that, we can plug it back into one of the original equations (or the expression derived in Part A) solve for the other variable. When this is done with the system of two equations from Parts A and B, what is the solution? Enter A, then B, as two numbers, separated by a comma. ► View Available Hint(s) A, B = [5] ΑΣΦ ?

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Part A - Isolating a Variable Isolating a variable in two equations is easiest when one of them has a coefficient of 1. Let's say we have the two equations 3A - B=5 2A + 3B = -4 ● ● and want to isolate one of the variables, such that it appears by itself on one side of the equation. Which of the following is an equation with one of the above variables isolated? ► View Available Hint(s) 2A-3B-4 B = 3A-5 3B-2A-4 B = 5-3A Submit Previous Answers Correct Part B - Substitution Now that we have one of the variables from Part A isolated, and written in terms of the other variable, we can now substitute this into the other of the two original equations. Which of the following options represents this? 3A (3A-5) = −4 2A +3(-5) = -4 2(B+5) +3B = −4 2A + 3(3A — 5) = −4 -
Transcribed Image Text:Part A - Isolating a Variable Isolating a variable in two equations is easiest when one of them has a coefficient of 1. Let's say we have the two equations 3A - B=5 2A + 3B = -4 ● ● and want to isolate one of the variables, such that it appears by itself on one side of the equation. Which of the following is an equation with one of the above variables isolated? ► View Available Hint(s) 2A-3B-4 B = 3A-5 3B-2A-4 B = 5-3A Submit Previous Answers Correct Part B - Substitution Now that we have one of the variables from Part A isolated, and written in terms of the other variable, we can now substitute this into the other of the two original equations. Which of the following options represents this? 3A (3A-5) = −4 2A +3(-5) = -4 2(B+5) +3B = −4 2A + 3(3A — 5) = −4 -
Part C - Solving for the Variables We now have an algebraic expression with only one variable, which can be solved. Once we have that, we can plug it back into one of the original equations (or the expression derived in Part A) to solve for the other variable. When this is done with the system of two equations from Parts A and B, what is the solution? Enter A, then B, as two numbers, separated by a comma. View Available Hint(s) A, B = VO ΠΙ ΑΣΦ ?
Transcribed Image Text:Part C - Solving for the Variables We now have an algebraic expression with only one variable, which can be solved. Once we have that, we can plug it back into one of the original equations (or the expression derived in Part A) to solve for the other variable. When this is done with the system of two equations from Parts A and B, what is the solution? Enter A, then B, as two numbers, separated by a comma. View Available Hint(s) A, B = VO ΠΙ ΑΣΦ ?
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