I Review Constants | Periodic TableThe spontaneity of a reaction depends both on the enthalpy change, AH, and entropy change, AS. Reactionsthat release energy produce more stable products, and the universe tends toward disorder. Thus, an exothermicreaction with a positive entropy change will always be spontaneous. Mathematically, this relationship can berepresented asWhat can be said about an endothermic reaction with a negative entropy change?• View Available Hint(s)AG - AH - тASO spontaneous at all temperatures.where AG is the change in Gibbs free energy and is the Kelvin temperature. If AG is negative, then thereaction is spontaneous. If AG is positive, then the reaction is nonspontaneous as written but spontaneous inthe reverse direction.O spontaneous at high temperatures.The reaction isO spontaneous at low temperatures.O spontaneous in the reverse direction at all temperatures.O nonspontaneous in either direction at all temperatures.SubmitPrevlous Anawerav Correct• Part BWhat can be said about an exothermic reaction with a negative entropy change?> View Available Hint(s)O spontaneous at all temperatures.O spontaneous at high temperatures.The reaction isO spontaneous at low temperatures.O spontaneous in the reverse direction at all temperatures.O nonspontaneous in either direction at all temperatures.SubmitPrevlous Anawerev Correct• Part CIf AH = -70.0 kJ and AS = -0.500 kJ/K, the reaction is spontaneous below a certain temperature. Calculate that temperature.Express your answer numerically in kelvins.• View Available Hint(s)Templates Symdols undo redo feset keyboard shortcuts Help250K=SubmitPrevlous AnawereX Incorrect; Try Again; 4 attempts remaining

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Part C IHAH 70.0 kJ and AS-4.500 k/K, the reaction is spontaneous below a certain temperature. Calculate that temperature. Express your answer numerically in kelvins. View Available Hintis) Tempare |Choơ reợo tes keyboard shortouts Heip 250 Submit Previou An x Incorrect: Try Again; 4 attempts remaining

Part C IHAH 70.0 kJ and AS-4.500 k/K, the reaction is spontaneous below a certain temperature. Calculate that temperature. Express your answer numerically in kelvins. View Available Hintis) Tempare |Choơ reợo tes keyboard shortouts Heip 250 Submit Previou An x Incorrect: Try Again; 4 attempts remaining

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Research is being carried out on cellulose as a source of chemicals for the production of fibers, coatings, and plastics. Cellulose consists of long chains of glucose molecules (C6H1206), so for the purposes of modeling the reaction we can consider the conversion of glucose to formaldehyde (H2CO). 1st attempt See Periodic Table O See Hint Calculate the heat of reaction for the conversion of 1 mole of glucose into formaldehyde, given the following thermochemical data: H,CO(g) + O,(g) –→ co,(g) - H,0(g) AP comb = -572.9 kJ/mol 6C(s) + 6H, (g) + 30, () → C,H12Og(s) AH= -1274.4 kJ/mol [CG)+0,() co,(] AHF= -393.5 kJ/mol » H,0(g) AHf= -285.8 kJ/mol What is the AHxn for the reaction below? → GH,CO (g) kJ
Consider the reactionN2(g) + 3H2(g)----->2NH3(g)Using the standard thermodynamic data in the tables linked above, calculate Grxn for this reaction at 298.15K if the pressure of each gas is 38.65 mm Hg.ANSWER: kJ/mol
Pls help ASAP.
Calculate the AS°rxn of the following reaction at 223°C and standard pressure. 1st attempt O See Hint C,H,(8) + 30,(g) . 200,(g) + 2H,0(g) AH°f, kJ/mol S°, J/mol K AG°F, kJ/mol C2H4(g) 52.3 219.5 68.1 O2(g) 205.0 CO2(g) -393.5 213.6 -394.4 H20(g) -241.8 188.7 -228.6 J/mol K
Consider the reaction2SO2(g) + O2(g)->2SO3(g)Using the standard thermodynamic data in the tables linked above, calculate deltaGrxn for this reaction at 298.15K if the pressure of each gas is 39.97 mm Hg.ANSWER: kJ/mol
For the reaction 3Fe₂O3(s) + H₂(g)- →2Fe3O4(s) + H₂O(g) AH° = -6.00 kJ and AS° = 88.7 J/K At standard conditions, this reaction would be product favored O O O O relatively high temperatures. at no temperature. at at all temperatures. at relatively low temperatures.
Calculate AGran in kJ, at 298K for the following reaction using the conditions given below. R = 8.314 J/mol.K SO3 (g) + H₂O (9) H₂SO4 (1) AGran = -90.5 (A) mol Pso3 = 0.20 atm, Pu,o = 0.88 atm Express your answer to one decimal place.
Hint: No calculations are required. For the reaction 2H₂O(1) 2H₂(g) + O₂(g) AH° 572 kJ and AS° = 327 J/K At standard conditions, this reaction would be product favored O at all temperatures. at no temperature. O at relatively low temperatures. O at relatively high temperatures.
Which statement best aligns with one of the three laws of thermodynamics? O AG--T(AS+AS) O AG-AU-PAV-TAS O AG-TAS O AG-T(AS-AS)