Part C - Determining the displacement of a spring The cable segment attached to the spring is at an angle of o = 50.0° from the ground. The spring has a spring constant of k = 15.5 kN/m . The pulley is attac the ceiling by rod BD that forms an angle 0 = 70.0° with the ceiling. The hanging mass causes a tension of 3408 N in rod BD. What is the displacement of the spring? Express your answer to three significant figures and include the appropriate units. > View Available Hint(s) s = 0.117 m

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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PART D

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### Learning Goal:
To draw the free-body diagram of a point particle, use the equations of equilibrium to find unknown forces, and understand how frictionless pulleys affect the transfer of force in a cable.

As shown, a mass is suspended from a cable that wraps around a frictionless and massless pulley. The cable connects to a linear elastic spring. For this problem, treat the pulley as a point particle at \( B \).
- **Figure 1**

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![Diagram 1](figure.jpg)
**Figure Description**: A diagram illustrating the system of interest. The figure shows a mass (`m`) hanging from a cable tied to a frictionless and massless pulley at point `B`. The cable is also connected to a linear elastic spring with a spring constant \( k \). The mass causes a tension in the rod `BD`. The angles provided are \( \theta \) and \( \phi \).

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### Part C - Determining the displacement of a spring
The cable segment attached to the spring is at an angle of \( \phi = 50.0^\circ \) from the ground. The spring has a spring constant of \( k = 15.5 \, \text{kN/m} \). The pulley is attached to the ceiling by rod `BD` that forms an angle \( \theta = 70.0^\circ \) with the ceiling. The hanging mass causes a tension of \( 3408 \, \text{N} \) in rod `BD`. What is the displacement of the spring?

Express your answer to three significant figures and include the appropriate units.

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**Answer Submission Form:**
- **Hint(s) Available**:
  - Previous Hints
- **Your Answer:**
  - \( s = 0.117 \, \text{m} \)

---

**Status**: 
- **Correct**: Correct answer is shown. Your answer \( 0.11699 \, \text{m} \) was either rounded differently or used a different number of significant figures than required for this part.

---

**Contextual Note**: 

In Part B, it was shown that the tension in a cable is constant around a frictionless pulley. The reason why the equations of equilibrium could be used here is because the values of \( \theta \) and \( \phi \) are not arbitrary. In fact, the geometry of the system is based on the equations of equilibrium
Transcribed Image Text:--- ### Learning Goal: To draw the free-body diagram of a point particle, use the equations of equilibrium to find unknown forces, and understand how frictionless pulleys affect the transfer of force in a cable. As shown, a mass is suspended from a cable that wraps around a frictionless and massless pulley. The cable connects to a linear elastic spring. For this problem, treat the pulley as a point particle at \( B \). - **Figure 1** --- ![Diagram 1](figure.jpg) **Figure Description**: A diagram illustrating the system of interest. The figure shows a mass (`m`) hanging from a cable tied to a frictionless and massless pulley at point `B`. The cable is also connected to a linear elastic spring with a spring constant \( k \). The mass causes a tension in the rod `BD`. The angles provided are \( \theta \) and \( \phi \). --- ### Part C - Determining the displacement of a spring The cable segment attached to the spring is at an angle of \( \phi = 50.0^\circ \) from the ground. The spring has a spring constant of \( k = 15.5 \, \text{kN/m} \). The pulley is attached to the ceiling by rod `BD` that forms an angle \( \theta = 70.0^\circ \) with the ceiling. The hanging mass causes a tension of \( 3408 \, \text{N} \) in rod `BD`. What is the displacement of the spring? Express your answer to three significant figures and include the appropriate units. --- **Answer Submission Form:** - **Hint(s) Available**: - Previous Hints - **Your Answer:** - \( s = 0.117 \, \text{m} \) --- **Status**: - **Correct**: Correct answer is shown. Your answer \( 0.11699 \, \text{m} \) was either rounded differently or used a different number of significant figures than required for this part. --- **Contextual Note**: In Part B, it was shown that the tension in a cable is constant around a frictionless pulley. The reason why the equations of equilibrium could be used here is because the values of \( \theta \) and \( \phi \) are not arbitrary. In fact, the geometry of the system is based on the equations of equilibrium
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