**Part C**Derive a formula for δ, the angle between the red and blue refracted rays in the diamond.Express the angle in terms of $ n_{\text{red}}, n_{\text{blue}}, $ and $ \theta_a $. Use $ n_{\text{air}} = 1 $. Note that any trig function entered in your answer must be followed by an argument in parentheses.**Formula:** \[ \delta = \sin^{-1}\left(\frac{\sin \theta_{\text{air}}}{n_{\text{red}}}\right) - \sin^{-1}\left(\frac{\sin \theta_{\text{air}}}{n_{\text{blue}}}\right) \]**Instructions:**Click "Submit" when you have completed your answer. If you wish to revise your submission, click "Previous Answers." A beam of white light is incident on the surface of a diamond at an angle $\theta_a$. (Figure 1) Since the index of refraction depends on the light's wavelength, the different colors that comprise white light will spread out as they pass through the diamond. The indices of refraction in diamond are $ n_{\text{red}} = 2.410 $ for red light and $ n_{\text{blue}} = 2.450 $ for blue light. The surrounding air has $ n_{\text{air}} = 1.000 $. Note that the angles in the figure are not to scale.**Figure 1 Description:**The diagram likely illustrates the refraction of a beam of white light as it enters a diamond from the air. It demonstrates how different wavelengths of light bend at different angles due to their distinct indices of refraction, resulting in a dispersion of colors.

Refractive index in diamond for red light nred=2.410Refractive index in diamond for blue lightnblue…

Part C Derive a formula for 6, the angle between the red and blue refracted rays in the diamond. Express the angle in terms of ► View Available Hint(s) ΠΠΙΑΣΦ 8 = sin Submit sin air nred Previous Answers red, blue, and a. Use nair = 1. Note that any trig function entered in your answer must be followed by an argument in parentheses. sin sin ? air n blue

Part C Derive a formula for 6, the angle between the red and blue refracted rays in the diamond. Express the angle in terms of ► View Available Hint(s) ΠΠΙΑΣΦ 8 = sin Submit sin air nred Previous Answers red, blue, and a. Use nair = 1. Note that any trig function entered in your answer must be followed by an argument in parentheses. sin sin ? air n blue

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Q1/ Group of rays stared from point (O) in a layer with velocity (2500) m/sec, then hit a contact (interface) of another layers with velocity (3500) m/sec. find: 1-Calculate the values of refraction angles in second media if the incidence angles are: 5, 10, 15, 20, 25, 30, 35, 40, 45 2-Draw the incidence and refraction rays.
As we saw in the video in step 1, total internal reflection can occur for cases where a light ray attempts to travel from a high index to low index medium. However, it can only occur for particular ranges of incident angles. The lowest possible incident angle for which total internal reflection occurs is called the critical angle. With = 1.50 and n₂ = 1.00, use the simulation to find the critical angle (in degrees). 1₂ 7₂. 1' Play around with different values of ₁, ₂, and 8₁. Try to find the critical angle for different values of n₁ and Note that total internal reflection is only possible in cases where n₁ > ₂.
Calculate the critical angle for the light traveling from glass (n glass= 1.54) to air (n=1.00). Express your answer in degrees. Normal format with 3 SF. air
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[Write true on the blank if the statement is TRUE. If FALSE, write false and supply the correct answer. Ex1. False; Speed True 1. Meter per second is the unit of acceleration. 2. Distance is a scalar quantity.] Ex2. 1. Diamonds sparkle because of total internal reflection. 2. The critical angle for total internal reflection happens when the angle of refraction is greater than 90°.
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I Review | Constants | Periodi The average distance between Jupiter and the sun is 7.78 × 1011 m and Jupiter's radius is 6.99 x 107 m. Part A Compute the angular size of Jupiter as seen from earth when the distance from earth to Jupiter is the same as the distance from the sun to Jupiter. Express your answer in radians. ? rad Submit Request Answer Part B Your telescope's objective lens has a focal length of 820 mm, and you use a 10 mm eyepiece to view Jupiter. What is the angular size of the image? Express your answer in radians. ? 0 = rad Submit Request Answer ( Return to Assignment Provide Feedback
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