Part C- Acid-base and solubility equilibria 1. Rinse 4 regular size test tubes and a 10 ml. measuring cylinder thoroughly with water. Number the test-tubes from 1 to 4 in a test tube rack. Into cach of test tubes 1 - 3 put a small amount of solid benzoic acid (put the same amount - about the size of a pea - in each test tube). 2. 3. Add 2 ml. (use the measuring cylinder) of water to tube 1 and shake to mix the contents. 4. Add 2 ml. (measuring cylinder) of 2 M HNO, to tube 2 and shake to mix the contents. 5. Rinse the measuring cylinder with water, then use it to add 2 ml of 2 M NAOH to tube 3 and shake for about 10 seconds to mix the contents. Rinse the measuring cylinder. 6. Pour about half of the solution from tube 3 into tube 4, than add 2 ml. of 2 M HNO3 to tube 4. 7. Allow the test tubes to stand for 2 or 3 minutes then record the appearance of the mixtures in each test tube. 8. Answer the questions on the results page relating to this equilibrium system. Results Test tube Observation 1. Solid benzoic acid + water 2. Solid benzoic acid + 2M HNO, 3. Solid benzoic acid + 2M NaOH 4. Solution from test tube 4 + 2M HNO, Precipitate forming Precipitate forming No reaction Turbid appearance Question Benzoic acid can dissociate in water: CgH3COOH(aq) CH3CO0 (aq) + H*(aq) What effect would removing H* by reacting it with OH to form water have on this equilibrium? Do your observations from test tubes 2, 3, and 4 support this?

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Part C - Acid-base and solubility equilibria
1.
Rinse 4 regular size test tubes and a 10 mL measuring cylinder thoroughly with water. Number the test-tubes from 1 to
4 in a test tube rack.
2.
Into each of test tubes 1 – 3 put a small amount of solid benzoic acid (put the same amount – about the size of a pea –
in each test tube).
3.
Add 2 mL (use the measuring cylinder) of water to tube 1 and shake to mix the contents.
4.
Add 2 mL (measuring cylinder) of 2 M HNO, to tube 2 and shake to mix the contents.
5.
Rinse the measuring cylinder with water, then use it to add 2 mL of 2 M NaOH to tube 3 and shake for about 10 seconds
to mix the contents. Rinse the measuring cylinder.
6.
Pour about half of the solution from tube 3 into tube 4, than add 2 mL of 2 M HNO3 to tube 4.
7.
Allow the test tubes to stand for 2 or 3 minutes then record the appearance of the mixtures in each test tube.
8.
Answer the questions on the results page relating to this equilibrium system.
Results
Test tube
Observation
1. Solid benzoic acid + water
Precipitate forming
2. Solid benzoic acid + 2M HNO3
Precipitate forming
3. Solid benzoic acid + 2M NaOH
4. Solution from test tube 4 + 2M HNO3
No reaction
Turbid appearance
Question
Benzoic acid can dissociate in water: C¢H5COOH(aq) C,H5CO0 (aq) + H*(aq)
What effect would removing H* by reacting it with OH- to form water have on this equilibrium? Do your observations
from test tubes 2, 3, and 4 support this?
Transcribed Image Text:Part C - Acid-base and solubility equilibria 1. Rinse 4 regular size test tubes and a 10 mL measuring cylinder thoroughly with water. Number the test-tubes from 1 to 4 in a test tube rack. 2. Into each of test tubes 1 – 3 put a small amount of solid benzoic acid (put the same amount – about the size of a pea – in each test tube). 3. Add 2 mL (use the measuring cylinder) of water to tube 1 and shake to mix the contents. 4. Add 2 mL (measuring cylinder) of 2 M HNO, to tube 2 and shake to mix the contents. 5. Rinse the measuring cylinder with water, then use it to add 2 mL of 2 M NaOH to tube 3 and shake for about 10 seconds to mix the contents. Rinse the measuring cylinder. 6. Pour about half of the solution from tube 3 into tube 4, than add 2 mL of 2 M HNO3 to tube 4. 7. Allow the test tubes to stand for 2 or 3 minutes then record the appearance of the mixtures in each test tube. 8. Answer the questions on the results page relating to this equilibrium system. Results Test tube Observation 1. Solid benzoic acid + water Precipitate forming 2. Solid benzoic acid + 2M HNO3 Precipitate forming 3. Solid benzoic acid + 2M NaOH 4. Solution from test tube 4 + 2M HNO3 No reaction Turbid appearance Question Benzoic acid can dissociate in water: C¢H5COOH(aq) C,H5CO0 (aq) + H*(aq) What effect would removing H* by reacting it with OH- to form water have on this equilibrium? Do your observations from test tubes 2, 3, and 4 support this?
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