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Part B. Standardization of Sodium hydroxide solution Balanced chemical equation: Trial 1 Trial 2 Trial 3 Mass of oxalic acid 0.1314g NA NA Initial burette reading 0.40mL Final burette reading 20.60 mL -0.40 mL 20.20 mL 20.60mL Volume NaOH added 20.20mL moles of oxalic acid 0:001m O.1314 3 = 0.00Im moles of NaOH added 0.002 m 2x 0.001m=0.002 Molarity of NaOH 0.IM

Part B. Standardization of Sodium hydroxide solution Balanced chemical equation: Trial 1 Trial 2 Trial 3 Mass of oxalic acid 0.1314g NA NA Initial burette reading 0.40mL Final burette reading 20.60 mL -0.40 mL 20.20 mL 20.60mL Volume NaOH added 20.20mL moles of oxalic acid 0:001m O.1314 3 = 0.00Im moles of NaOH added 0.002 m 2x 0.001m=0.002 Molarity of NaOH 0.IM

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Experiment 11 Data to be completed and uploaded. Only one trial! (There is no part A) Part B. Standardization of Sodium hydroxide solution Balanced chemical equation: Trial 1 Trial 2 Trial 3 Mass of oxalic acid _0.1314g_ NA NA Initial burette reading _0.40mL Final burette reading 20.60 me -0.40 mL 20.20 mL Volume NaOH added 20.60mL · 20.20m moles of oxalic acid 0:001m O.1314 g molcs = 0.00Im う11*メP moles of NaOH added 90g Actd 0.002 m 2x 0.00lm=0.002 Molarity of NaOH 0.IM oF NaOH=welas Volume molavit 2020ML
Transcribed Image Text:Experiment 11 Data to be completed and uploaded. Only one trial! (There is no part A) Part B. Standardization of Sodium hydroxide solution Balanced chemical equation: Trial 1 Trial 2 Trial 3 Mass of oxalic acid _0.1314g_ NA NA Initial burette reading _0.40mL Final burette reading 20.60 me -0.40 mL 20.20 mL Volume NaOH added 20.60mL · 20.20m moles of oxalic acid 0:001m O.1314 g molcs = 0.00Im う11*メP moles of NaOH added 90g Actd 0.002 m 2x 0.00lm=0.002 Molarity of NaOH 0.IM oF NaOH=welas Volume molavit 2020ML
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