Part b show the change. change null hypotheseis x >14 to what is in red in Part b. find reject and excepted for x>15 and x<=15. recaluate alpha and beta

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Part b show the change. change null hypotheseis x >14 to what is in red in Part b. find reject and excepted for x>15 and x<=15.

recaluate alpha and beta

alpha = P(reject HO|HO is true) = P(X< =14|theta=0.9) =
beta P(accept HO|H1 is true) = P(X>14|theta =0.6) =
HO: theta=0.9
H1: theta-0.6
X-Bin(n=20, theta)
accept: X>14 => X-15,16,17,18,19,20
reject: X<=14
X=0,1,2,.14
accept: X>15
I
reject:X<=15
alpha=
beta-
Transcribed Image Text:alpha = P(reject HO|HO is true) = P(X< =14|theta=0.9) = beta P(accept HO|H1 is true) = P(X>14|theta =0.6) = HO: theta=0.9 H1: theta-0.6 X-Bin(n=20, theta) accept: X>14 => X-15,16,17,18,19,20 reject: X<=14 X=0,1,2,.14 accept: X>15 I reject:X<=15 alpha= beta-
Suppose that the manufacturer a of a new medication wants to test the null
hypothesis 6 = 0.90 against the alternative hypothesis 0 = 0.60, His (test statistid is
X, the observed number of successes (recoveries) in 20 tríals, and he will accept the
null hypothesis if x > 14; otherwise, he will reject it. Find a and ß.
%3D
Solution The acceptance region for the null hypothesis is x = 15, 16, 17, 18, 19, and
20, and, correspondingly, therejection region (or critical region) is x = 0, 1, 2, ...,
Therefore,
14.
a = P(X S14; 0 = 0.90) = 0.0114
and
B = P(X > 14; 0 = 0.60) = 0,1255
%3D
Transcribed Image Text:Suppose that the manufacturer a of a new medication wants to test the null hypothesis 6 = 0.90 against the alternative hypothesis 0 = 0.60, His (test statistid is X, the observed number of successes (recoveries) in 20 tríals, and he will accept the null hypothesis if x > 14; otherwise, he will reject it. Find a and ß. %3D Solution The acceptance region for the null hypothesis is x = 15, 16, 17, 18, 19, and 20, and, correspondingly, therejection region (or critical region) is x = 0, 1, 2, ..., Therefore, 14. a = P(X S14; 0 = 0.90) = 0.0114 and B = P(X > 14; 0 = 0.60) = 0,1255 %3D
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