Problem 2: A block with a mass of m = 1.5 kg rests on a wooden plank. The coefficient ofstatic friction between the block and the plank is u, = 0.84. One end of the board is attached to ahinge so that the other end can be lifted forming an angle, 0, with respect to the ground. Assume thex-axis is along the plank as shown in the figure.m Part (b) Assuming the x-direction is along the plank as shown, find an expression for the component of the force of gravity in the y-direction, Fpy,perpendicular to the plank in terms of given quantities and variables available in the palette.Fgy=

The force of gravity acting on the block acts vertically downwards on the block. And since the block…

Answered: Part (b) Assuming the x-direction is…

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Part (b) Assuming the x-direction is along the plank as shown, find an expression for the component of the force of gravity in the y-direction, Fgy, perpendicular to the plank in terms of given quantities and variables available in the palette. F