Part B A solution of rubbing alcohol is 71.9 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a 84.8 mL sample of the rubbing alcohol solution? Express your answer to three significant figures. • View Available Hint(s) ? Milliliters of isopropanol = mL Submit Part C How many liters of a 3.35 M K2SO4 solution are needed to provide 97.5 g of K2SO4(molar mass 174.01 g/mol)? Recall that M is equivalent to mol/L. Express your answer to three significant figures. • View Available Hint(s) 国
Part B A solution of rubbing alcohol is 71.9 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a 84.8 mL sample of the rubbing alcohol solution? Express your answer to three significant figures. • View Available Hint(s) ? Milliliters of isopropanol = mL Submit Part C How many liters of a 3.35 M K2SO4 solution are needed to provide 97.5 g of K2SO4(molar mass 174.01 g/mol)? Recall that M is equivalent to mol/L. Express your answer to three significant figures. • View Available Hint(s) 国
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Part B
A solution of rubbing alcohol is 71.9 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a 84.8 mL sample of the rubbing alcohol solution?
Express your answer to three significant figures.
• View Available Hint(s)
?
Milliliters of isopropanol =
mL
Submit
▼
Part C
How many liters of a 3.35 M K2SO4 solution are needed to provide 97.5 g of K2SO4(molar mass 174.01 g/mol)? Recall that M is equivalent to mol/L.
Express your answer to three significant figures.
• View Available Hint(s)
?
Volume of K2 SO4 =
L
Submit
國](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6d3a7fcd-1e86-46d8-8028-8f687275a741%2F4584d93e-981b-482e-a7ee-d5a7122086ed%2Ffl3tha_processed.png&w=3840&q=75)
Transcribed Image Text:Part B
A solution of rubbing alcohol is 71.9 % (v/v) isopropanol in water. How many milliliters of isopropanol are in a 84.8 mL sample of the rubbing alcohol solution?
Express your answer to three significant figures.
• View Available Hint(s)
?
Milliliters of isopropanol =
mL
Submit
▼
Part C
How many liters of a 3.35 M K2SO4 solution are needed to provide 97.5 g of K2SO4(molar mass 174.01 g/mol)? Recall that M is equivalent to mol/L.
Express your answer to three significant figures.
• View Available Hint(s)
?
Volume of K2 SO4 =
L
Submit
國
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