Part A When an object like a piece of graphite is heated to 1000 K, it glows red. When the temperature is increased to around 3000 K, the color of emitted light becomes orange. What is the reason for this change in color? O The average wavelength of the photons emitted increases with increasing temperature. O The average energy of the photons emitted increases as the temperature increases. O The speed of the photons (quantized packets of radiant energy) increases within creasing temperature.

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Transcription for Educational Website**

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**Part A**

When an object like a piece of graphite is heated to 1000 K, it glows red. When the temperature is increased to around 3000 K, the color of emitted light becomes orange. What is the reason for this change in color?

- O The average wavelength of the photons emitted increases with increasing temperature.
- O The average energy of the photons emitted increases as the temperature increases.
- O The speed of the photons (quantized packets of radiant energy) increases with increasing temperature.

**[Submit]**  **[Request Answer]**

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**Explanation:**

This question relates to the phenomenon of blackbody radiation, which describes how objects emit light based on their temperature. As the temperature of an object increases, the light emitted shifts to shorter wavelengths or higher energy levels, thus changing color. 

**Note:** This question explores the relationship between temperature and the emitted light's characteristics, allowing students to understand concepts such as photon energy and wavelength.
Transcribed Image Text:**Transcription for Educational Website** --- **Part A** When an object like a piece of graphite is heated to 1000 K, it glows red. When the temperature is increased to around 3000 K, the color of emitted light becomes orange. What is the reason for this change in color? - O The average wavelength of the photons emitted increases with increasing temperature. - O The average energy of the photons emitted increases as the temperature increases. - O The speed of the photons (quantized packets of radiant energy) increases with increasing temperature. **[Submit]** **[Request Answer]** --- **Explanation:** This question relates to the phenomenon of blackbody radiation, which describes how objects emit light based on their temperature. As the temperature of an object increases, the light emitted shifts to shorter wavelengths or higher energy levels, thus changing color. **Note:** This question explores the relationship between temperature and the emitted light's characteristics, allowing students to understand concepts such as photon energy and wavelength.
The image contains a multiple-choice question related to atomic physics, specifically about hydrogen atoms and photon emissions. It appears in a typical online educational setting with options to select answers.

**Question:**
Which of the following statements are true?
*Check all that apply.*

**Options:**
- [ ] A hydrogen atom in the \( n = 3 \) state can emit light at only two specific wavelengths.
- [ ] A hydrogen atom in the \( n = 4 \) state is at a lower energy than one in the \( n = 3 \) state.
- [ ] The energy of an emitted photon equals the energy difference of the two states involved in the emission.

Below the options, there are two buttons:
- **Submit**
- **Request Answer**
Transcribed Image Text:The image contains a multiple-choice question related to atomic physics, specifically about hydrogen atoms and photon emissions. It appears in a typical online educational setting with options to select answers. **Question:** Which of the following statements are true? *Check all that apply.* **Options:** - [ ] A hydrogen atom in the \( n = 3 \) state can emit light at only two specific wavelengths. - [ ] A hydrogen atom in the \( n = 4 \) state is at a lower energy than one in the \( n = 3 \) state. - [ ] The energy of an emitted photon equals the energy difference of the two states involved in the emission. Below the options, there are two buttons: - **Submit** - **Request Answer**
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