▼ Part A What must the charge (sign and magnitude) of a particle of mass 1.46 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 610 N/C ? Use 9.80 m/s² for the magnitude of the free-fall acceleration. ▸ View Available Hint(s) —| ΑΣΦ Submit Part B 97| ΑΣΦ ? What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight? Use 1.67x10-27 kg for the mass of a proton, 1.60×10-19 C for the magnitude of the charge on an electron, and 9.80 m/s² for the magnitude of the free-fall acceleration. ► View Available Hint(s) Submit C ? N/C

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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Item 5
Part A
What must the charge (sign and magnitude) of a particle of mass 1.46 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 610 N/C ?
Use 9.80 m/s² for the magnitude of the free-fall acceleration.
► View Available Hint(s)
—| ΑΣΦ
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Part B
?
Submit
What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight?
Use 1.67×10-27 kg for the mass of a proton, 1.60×10-19 C for the magnitude of the charge on an electron, and 9.80 m/s² for the magnitude of the free-fall acceleration.
► View Available Hint(s)
VE ΑΣΦ
C
?
N/C
Transcribed Image Text:Item 5 Part A What must the charge (sign and magnitude) of a particle of mass 1.46 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 610 N/C ? Use 9.80 m/s² for the magnitude of the free-fall acceleration. ► View Available Hint(s) —| ΑΣΦ Submit Part B ? Submit What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight? Use 1.67×10-27 kg for the mass of a proton, 1.60×10-19 C for the magnitude of the charge on an electron, and 9.80 m/s² for the magnitude of the free-fall acceleration. ► View Available Hint(s) VE ΑΣΦ C ? N/C
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