Part a) What fraction of the hydrogen bonds would be broken at 27 celsius (room temperature) and how many hydrogen bonds would be broken at 100 celsius? Part b) Using your answer from Part a, explain why proteins are stored on ice?
A H-bond has a delta u of around 1 kcal/mol. Answer both part a and part b please.
Part a) What fraction of the hydrogen bonds would be broken at 27 celsius (room temperature) and how many hydrogen bonds would be broken at 100 celsius?
Part b) Using your answer from Part a, explain why proteins are stored on ice?
A) At room temperature, the energy available is in form of thermal energy which is equal to kBT where kB is Boltzmann constant and T is temperature in terms of Kelvin. kB has a value of 3.297 * 10-27 kcal/K. In order to convert temperature in oC scale to Kelvin scale, add 273 to temperature given in oC. So, 27oC = (27 +273)K = 300 K
Thermal energy at room temperature
At room temperature thermal energy available is 0.59kcal/mol but the energy required to break the hydrogen bond is 1kcal/mol. So, fraction of the H-bond that would be broken at room temperature is 0.59 .
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