Part A The rate constant for a certain reaction is k = 8.60x10s. If the initial reactant concentration was 0.800 mol L-1, what will the concentration be after 18.0 minutes? Express your answer with the appropriate units. • View Available Hint(s) Tempjates Symbols undo redo Teset keyboard shortcuts Help Value Units Submit Part B Azero-order reaction has a constant rate of 2.30x10* mol L-'s.If after 80.0 seconds the concentration has dropped to 8.00x102 mol L-1, what was the initial concentration? Express your answer with the appropriate units. View Available Hint(s) Tempiates Symbols undo rego fes keyboard shortcuts Help Value Units Submit Provide Feedback

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Leaming Goal:
To understand how to use integrated rate laws to solve for concentration.
• Part A
A car starts at mile marker 145 on a highway and drives at 55 mi/hr in the direction of
decreasing marker numbers. What mile marker will the car reach after 2 hours?
The rate constant for a certain reaction is k = 8.60x103 s. If the initial reactant concentration was 0.800 mol L, what will the concentration be after 18.0 minutes?
This problem can easily be solved by calculating how far the car travels and subtracting that
distance from the starting marker of 145.
Express your answer with the appropriate units.
55 mi/hr x 2 hr = 110 miles traveled
• View Available Hint(s)
milemarker 145 – 110 miles = milemarker 35
If we were to write a formula for this calculation, we might express it as follows:
Tempjates Symbols undo redo feset keyboard shortcuts Helo
milemarker = milemarkero – (speed x time)
Value
Units
where milemarker is the current milemarker and milernarkero is the initial milemarker.
Similariy, the integrated rate law for a zero-order reaction is expressed as follows:
Submit
[A] = [A]o - rate x time
or
Part B
[A] = [A]u - kt
since
Azero-order reaction has a constant rate of 2.30x10 mol L-s. If after 80.0 seconds the concentration has dropped to 8.00x102 molL-, what was the initial concentration?
Express your answer with the appropriate units.
Figure
< 1 of 2 >
> View Available Hint(s)
zero-order
Tempjates Symbols undo redo Teset keyboard shortcuts Help
Value
Units
Submit
[A]
Provide Feedback
time
Transcribed Image Text:Leaming Goal: To understand how to use integrated rate laws to solve for concentration. • Part A A car starts at mile marker 145 on a highway and drives at 55 mi/hr in the direction of decreasing marker numbers. What mile marker will the car reach after 2 hours? The rate constant for a certain reaction is k = 8.60x103 s. If the initial reactant concentration was 0.800 mol L, what will the concentration be after 18.0 minutes? This problem can easily be solved by calculating how far the car travels and subtracting that distance from the starting marker of 145. Express your answer with the appropriate units. 55 mi/hr x 2 hr = 110 miles traveled • View Available Hint(s) milemarker 145 – 110 miles = milemarker 35 If we were to write a formula for this calculation, we might express it as follows: Tempjates Symbols undo redo feset keyboard shortcuts Helo milemarker = milemarkero – (speed x time) Value Units where milemarker is the current milemarker and milernarkero is the initial milemarker. Similariy, the integrated rate law for a zero-order reaction is expressed as follows: Submit [A] = [A]o - rate x time or Part B [A] = [A]u - kt since Azero-order reaction has a constant rate of 2.30x10 mol L-s. If after 80.0 seconds the concentration has dropped to 8.00x102 molL-, what was the initial concentration? Express your answer with the appropriate units. Figure < 1 of 2 > > View Available Hint(s) zero-order Tempjates Symbols undo redo Teset keyboard shortcuts Help Value Units Submit [A] Provide Feedback time
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