Part A The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m1 = 95.0 kg and length L = 5.30 m is supported by two vertical massless strings. String A is attached at a distance d = 1.10 m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 3500 kg is supported by the crane at a distance x = 5.10 m from the left end of the bar. Throughout this problem, positive torque is counterclockwise and use 9.80 m/s² for the magnitude of the acceleration due to gravity. Figure String B String A x L m2 mi Find TA, the tension in string A. Express your answer in newtons using three significant figures. ▸ View Available Hint(s) TA = 1.61×105 N Submit Previous Answers Correct Correct answer is shown. Your answer 161432.4 N was either rounded differently or used a different number of significant figures than required for this part. Important: If you use this answer in later parts, use the full unrounded value in your calculations. 1 of 1 ▾ Part B Find TB, the magnitude of the tension in string B. Express your answer in newtons using three significant figures. View Available Hint(s) Hint 1. Two different methods to find TB There are two ways to find TB. One way is to balance the torques as you did in the calculation of TA using a different rotation axis. In this case, a convenient axis passes through the point at which string A is attached to the bar. The second, easier, method is to use the second equation for static equilibrium, ΣΕ=0. Hint 2. Direction of forces Since both strings are vertical, all forces acting on the bar are vertical. Ο ΑΣΦ TB = 1566.5 Submit Previous Answers Request Answer × Incorrect; Try Again ? N
Part A The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m1 = 95.0 kg and length L = 5.30 m is supported by two vertical massless strings. String A is attached at a distance d = 1.10 m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 3500 kg is supported by the crane at a distance x = 5.10 m from the left end of the bar. Throughout this problem, positive torque is counterclockwise and use 9.80 m/s² for the magnitude of the acceleration due to gravity. Figure String B String A x L m2 mi Find TA, the tension in string A. Express your answer in newtons using three significant figures. ▸ View Available Hint(s) TA = 1.61×105 N Submit Previous Answers Correct Correct answer is shown. Your answer 161432.4 N was either rounded differently or used a different number of significant figures than required for this part. Important: If you use this answer in later parts, use the full unrounded value in your calculations. 1 of 1 ▾ Part B Find TB, the magnitude of the tension in string B. Express your answer in newtons using three significant figures. View Available Hint(s) Hint 1. Two different methods to find TB There are two ways to find TB. One way is to balance the torques as you did in the calculation of TA using a different rotation axis. In this case, a convenient axis passes through the point at which string A is attached to the bar. The second, easier, method is to use the second equation for static equilibrium, ΣΕ=0. Hint 2. Direction of forces Since both strings are vertical, all forces acting on the bar are vertical. Ο ΑΣΦ TB = 1566.5 Submit Previous Answers Request Answer × Incorrect; Try Again ? N
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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