Part A Suppose the net vertical impulse on the 50-kg kangaroo due to all external forces was +100 N-s. Find its vertical component of velocity when it leaves the ground. Assume that the kangaroo is initially at rest. Express your answer with the appropriate units. Value Units Av =

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it ericalat wen aking ef and len
Höpping is an efficient method of locomotion for the kagaroo (see the figure above). When the kangaroo is in the air, the Earth-kangaroo system has a combination of gravitational potential energy and kinetic energy. When
the kangaroo lands, its Achilles tendons and the attached muscles stretch-a form of elastic potential energy. This elastic potential energy is used along with additional muscle tension to launch the kangaroo off the ground for
the next hop. In the red kangaroo, more than 50% of the total energy used during each hop is recovered elastic potential energy. This is so efficient that the kangaroo's metabolic rate actually decreases slightly as its
hopping speed increases from 8 km/h to 25 km/h.
The horizontal and vertical force components exerted by a firm surface on a kangaroo's feet while it hops are shown in the fiqure below. The vertical force Ns on Ky vanies: when the kangaroo is not touching the surface S
the force is zero, when it is pushing off, the force is about three times the gravitational force that Earth exerts on the kangaroo, The surtace exerts a backward horizontal force (F ) on the kangaroo's foot while it
lands and a fonward horizontal force as it pushes off for the next hop similar to what happens to a human foot when landing in tront of the body and when pushing off for another step when behind the body.
(c) F
1500
N
TO00
500
500
Transcribed Image Text:it ericalat wen aking ef and len Höpping is an efficient method of locomotion for the kagaroo (see the figure above). When the kangaroo is in the air, the Earth-kangaroo system has a combination of gravitational potential energy and kinetic energy. When the kangaroo lands, its Achilles tendons and the attached muscles stretch-a form of elastic potential energy. This elastic potential energy is used along with additional muscle tension to launch the kangaroo off the ground for the next hop. In the red kangaroo, more than 50% of the total energy used during each hop is recovered elastic potential energy. This is so efficient that the kangaroo's metabolic rate actually decreases slightly as its hopping speed increases from 8 km/h to 25 km/h. The horizontal and vertical force components exerted by a firm surface on a kangaroo's feet while it hops are shown in the fiqure below. The vertical force Ns on Ky vanies: when the kangaroo is not touching the surface S the force is zero, when it is pushing off, the force is about three times the gravitational force that Earth exerts on the kangaroo, The surtace exerts a backward horizontal force (F ) on the kangaroo's foot while it lands and a fonward horizontal force as it pushes off for the next hop similar to what happens to a human foot when landing in tront of the body and when pushing off for another step when behind the body. (c) F 1500 N TO00 500 500
(b)
Nky
(e) FsK
1500
Pushing forward
when taking off
Nsk
1000
0.4 6)
-Pushing back
when landing
Fsak
500
0.2
0.4
500
Feky
v Part A
Suppose the net vertical impulse on the 50-kg kangaroo due to all external forces was +100 N- s. Find its vertical component of velocity when it leaves the ground. Assume that the kangaroo is initially at rest.
Express your answer with the appropriate units.
Value
Units
Ar =
Transcribed Image Text:(b) Nky (e) FsK 1500 Pushing forward when taking off Nsk 1000 0.4 6) -Pushing back when landing Fsak 500 0.2 0.4 500 Feky v Part A Suppose the net vertical impulse on the 50-kg kangaroo due to all external forces was +100 N- s. Find its vertical component of velocity when it leaves the ground. Assume that the kangaroo is initially at rest. Express your answer with the appropriate units. Value Units Ar =
Expert Solution
Step 1

Mass of kangaroo (m)= 50 kg Impulse due to all external forces (I) = 100 N.s Initial speed of kangaroo (u) = 0 

 

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