Part A If the diameter of a hole is 4.500 mm, what should be the diameter of a rivet at 23.0°C, if its diameter is to equal that of the hole when the rivet is cooled to -78.0°C, the temperature of dry ice? Assume that the expansion coefficient of aluminum is 2.4 x 10-5 (°C)-¹ and remains constant. Express your answer in milimeters to four significant figures. d= Submit 17 ΑΣΦ Request Answer SE ? mm

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Aluminum rivets used in airplane construction are
made slightly larger than the rivet holes and cooled by
"dry ice" (solid CO₂) before being driven.
Part A
If the diameter of a hole is 4.500 mm, what should be the diameter of a rivet at 23.0°C, if its diameter is to equal that of the hole
when the rivet is cooled to -78.0°C, the temperature of dry ice? Assume that the expansion coefficient of aluminum is
2.4 x 10-5 (°C)-¹ and remains constant.
-1
Express your answer in milimeters to four significant figures.
d =
Submit
15. ΑΣΦ
Request Answer
?
Review Constants
mm
Transcribed Image Text:Aluminum rivets used in airplane construction are made slightly larger than the rivet holes and cooled by "dry ice" (solid CO₂) before being driven. Part A If the diameter of a hole is 4.500 mm, what should be the diameter of a rivet at 23.0°C, if its diameter is to equal that of the hole when the rivet is cooled to -78.0°C, the temperature of dry ice? Assume that the expansion coefficient of aluminum is 2.4 x 10-5 (°C)-¹ and remains constant. -1 Express your answer in milimeters to four significant figures. d = Submit 15. ΑΣΦ Request Answer ? Review Constants mm
Expert Solution
Step 1

Diameter of a hole or rivet at -78 degree Celsius, d=4.50×10-3 m

Length of the rivet at -78 degree Celsius, L=πd=0.01413 m

Expansion coefficient of Aluminum, α=2.4×10-5/°C

The diameter at 23 degree Celsius is to be evaluated, D

The Length of the Rivet at 23 degree Celsius would be L'

L' can be formulated as:L'=L+LαTT=Tf-Ti       =23°C--78°C       =101°C

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