Part A Determine the magnitude and direction of the electric field at point 1 in (Figure 1) O E = (2500 V/m, up) Figure 1 of 1 O E = (2500 V/m, down) O E = (7500 V/m, up) 75 V 50 V O E = (3750 V/m, down) %3D 25 V OV Submit Request Answer Part B cm Determine the magnitude and direction of the electric field at point 2 in (Figure 1). I cm O E - (2500 V/m, up)

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Chapter1: Units, Trigonometry. And Vectors
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26.10. Please help with part A and B of this problem. thank you! 

<HW5 Ch 26
Problem 26.10
2 of
Review | Cons
Part A
Determine the magnitude and direction of the electric field at point 1 in (Figure 1).
O E = (2500 V/m, up)
Figure
< 1 of 1
(2500 V/m, down)
>
O E = (7500 V/m, up)
75 V
50 V
O E = (3750 V/m, down)
25 V
OV
Submit
Request Answer
Part B
I cm
Determine the magnitude and direction of the electric field at point 2 in (Figure 1).
I cm
O E = (2500 V/m, up)
P Pearson
Copyright © 2020 Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy I Permissions I Contact UsI
ch
EPIC
ASUS
Transcribed Image Text:<HW5 Ch 26 Problem 26.10 2 of Review | Cons Part A Determine the magnitude and direction of the electric field at point 1 in (Figure 1). O E = (2500 V/m, up) Figure < 1 of 1 (2500 V/m, down) > O E = (7500 V/m, up) 75 V 50 V O E = (3750 V/m, down) 25 V OV Submit Request Answer Part B I cm Determine the magnitude and direction of the electric field at point 2 in (Figure 1). I cm O E = (2500 V/m, up) P Pearson Copyright © 2020 Pearson Education Inc. All rights reserved. Terms of Use | Privacy Policy I Permissions I Contact UsI ch EPIC ASUS
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