Part A An alpha particle with kinetic energy 11.5 MeV makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has What is the distance of closest approach? an initial nonzero angular momentum (with respect Express your answer in meters, to the stationary lead nucleus) of magnitude .ph, where p is the magnitude of the initial momentum of the alpha particle and b=1.30 x 10. (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number of lead is 82. The alpha particle is a helium nucleus, with atomic number 2.) Request Answer Part B Repeat for b 1.00 10 Express your answer in meters.c Part B Repeat for b-1.00-10-13 m Express your answer in meters. Η ΜΕ ΑΣΦ 40 ? E

Modern Physics
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Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
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Chapter13: Nuclear Structure
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Part A
An alpha particle with kinetic energy 11.5 MeV makes a collision with lead nucleus, but it is not "aimed" at the center of
the lead nucleus, and has
What is the distance of closest approach? an initial nonzero angular momentum (with respect
Express your answer in meters, to the stationary lead nucleus) of magnitude .ph, where p is the magnitude of the
initial momentum of the alpha particle and b=1.30 x 10. (Assume that the lead nucleus remains stationary and that
it may be treated as a point charge. The atomic number of lead is 82. The alpha particle is a helium nucleus, with
atomic number 2.)
Request Answer
Part B
Repeat for b 1.00 10
Express your answer in meters.c
Part B
Repeat for b-1.00-10-13 m
Express your answer in meters.
Η ΜΕ ΑΣΦ
40
?
E
Transcribed Image Text:Part A An alpha particle with kinetic energy 11.5 MeV makes a collision with lead nucleus, but it is not "aimed" at the center of the lead nucleus, and has What is the distance of closest approach? an initial nonzero angular momentum (with respect Express your answer in meters, to the stationary lead nucleus) of magnitude .ph, where p is the magnitude of the initial momentum of the alpha particle and b=1.30 x 10. (Assume that the lead nucleus remains stationary and that it may be treated as a point charge. The atomic number of lead is 82. The alpha particle is a helium nucleus, with atomic number 2.) Request Answer Part B Repeat for b 1.00 10 Express your answer in meters.c Part B Repeat for b-1.00-10-13 m Express your answer in meters. Η ΜΕ ΑΣΦ 40 ? E
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