Part 4 of 5for the 90% confidence intervalZa/2Za/2=%3DPart 5 of 5Za/2for the 85% confidence intervalZa/2= Find each of the following. Enter your answers rounded to at least two decimal places.Part 1 of 5for the 95% confidence intervalZ a/2%3DZa/2=Part 2 of 5for the 98% confidence intervalZ a/2Za/2=Part 3 of 5for the 99% confidence intervalZ a/2Za/2

We use standard normal Z distribution table to find the required critical value.

Answered: Part 4 of 5 Z/2 for the 90% confidence…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose you have a model Y = B₁ + B₂X₂ + uż that satisfies all CNLRM assumption with 8 observations, and the o2 = 36. What is the 95% confidence interval of o²? (17.17, 98.19) (18.63, 132.46) (17.75, 145.56) (14.95, 174.62) Do not have enough information
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We've seen how to compare the means of two samples with known population variances (refer, for instance, to Example 4 in Recitation 11), but when we need to compare the means of two samples with unknown (but assumed to be equal) population variances, a method called 'variance pooling' needs to be used to find the 'pooled sample variance' that should be used when calculating the confidence interval. The pooled variance is given by si (n1 - 1) + s5 (n2 - Spool = n, +n, -2 with v=n, +n, - 2 degrees of freedom (see page 308 of your e-book). Now look at the example below. Production engineers need to compare the average efficiencies of two production processes. Process 1 and Process 2 are sampled 11 and 15 times and they yielded average efficiencies of 80 and 75 (out of 100), respectively. The sample standard deviations are 6 and 3, again, respectively. Help them construct a 99% confidence interval, assuming that efficiency values are Normally distributed with equal variances. Click here to…
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Part 4 of 5 Z/2 for the 90% confidence interval Za/2= Part 5 of 5 Z2 for the 85% confidence interval Za/2