Part 2) The equation describing the vertical displacement from equilibrium of a wave on a string is given by: У(х, t) — 4.77 sin(2.96х-2.93t +0.911) cm. where x is in cm and t is in s. What is the wavelength, frequency, and speed of the wave? cm f = Hz U = cm/s Part 3) What is the displacement of the piece of rope located at x = 2.28 cm at t = 2.43 s. y = cm

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter13: Mechanical Waves
Section: Chapter Questions
Problem 35P
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Part 2)
The equation describing the vertical displacement from equilibrium of a wave on a string is given by:
y(x, t) = 4.77 sin(2.96x-2.93t + 0.911) cm.
where x is in cm and t is in s. What is the wavelength, frequency, and speed of the wave?
=
cm
f =
Hz
U =
cm/s
Part 3)
What is the displacement of the piece of rope located at x = 2.28 cm at t =
2.43 s.
y =
cm
Transcribed Image Text:Part 2) The equation describing the vertical displacement from equilibrium of a wave on a string is given by: y(x, t) = 4.77 sin(2.96x-2.93t + 0.911) cm. where x is in cm and t is in s. What is the wavelength, frequency, and speed of the wave? = cm f = Hz U = cm/s Part 3) What is the displacement of the piece of rope located at x = 2.28 cm at t = 2.43 s. y = cm
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