Part 2 of 2 (b) Find the area under the standard normal curve to the left of z= -0.94. The area to the left of z=-0.94 is -0.8264 X Ś Skip Part Recheck Try again Save For Later SL erms of Use | Privacy C
Part 2 of 2 (b) Find the area under the standard normal curve to the left of z= -0.94. The area to the left of z=-0.94 is -0.8264 X Ś Skip Part Recheck Try again Save For Later SL erms of Use | Privacy C
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![Part 2 of 2
(b) Find the area under the standard normal curve to the left of \( z = -0.94 \).
The area to the left of \( z = -0.94 \) is \[ \underline{ -0.8264 } \] .
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(Note: The value given in the answer box \(-0.8264\) appears to be incorrect as indicated by the red 'x' mark.)
### Explanation
In this problem, you are asked to find the area under the standard normal distribution curve to the left of a given z-score (\( z = -0.94 \)). The standard normal distribution, also known as the z-distribution, has a mean of 0 and a standard deviation of 1.
The area under the curve to the left of a z-score represents the cumulative probability of obtaining a value less than that z-score. This is typically found using standard normal distribution tables or statistical software which enables you to find the cumulative probability associated with a specific z-score. For \( z = -0.94 \), the correct value should be positive and would be found using one of these methods.
If the value were calculated correctly, it should be approximately 0.1736, not a negative value. This area represents the cumulative probability from the far left of the curve to the point where \( z = -0.94 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2a2559e1-167d-4bea-82a2-fac9ce901e5e%2F732b3131-8a47-439a-9c06-f8e63ba333ac%2Fpw9aifh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Part 2 of 2
(b) Find the area under the standard normal curve to the left of \( z = -0.94 \).
The area to the left of \( z = -0.94 \) is \[ \underline{ -0.8264 } \] .
Buttons available:
- X (Close)
- Recheck
- Try again
- Skip Part
- Save For Later
- Submit
(Note: The value given in the answer box \(-0.8264\) appears to be incorrect as indicated by the red 'x' mark.)
### Explanation
In this problem, you are asked to find the area under the standard normal distribution curve to the left of a given z-score (\( z = -0.94 \)). The standard normal distribution, also known as the z-distribution, has a mean of 0 and a standard deviation of 1.
The area under the curve to the left of a z-score represents the cumulative probability of obtaining a value less than that z-score. This is typically found using standard normal distribution tables or statistical software which enables you to find the cumulative probability associated with a specific z-score. For \( z = -0.94 \), the correct value should be positive and would be found using one of these methods.
If the value were calculated correctly, it should be approximately 0.1736, not a negative value. This area represents the cumulative probability from the far left of the curve to the point where \( z = -0.94 \).
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