Part 2 of 2 (b) Find the 70" percentile of the number of apps. Round the answer to two decimal places. The 70" percentile of the number of apps is

MATLAB: An Introduction with Applications
6th Edition
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Author:Amos Gilat
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How many apps? According to a website, the mean number of apps on a smartphone in the United States is 90. Assume the number of apps is normally
distributed with mean 90 and standard deviation 21.
6.1 The Normal Curve
Convert nermativalues tojssCAresii bri7 oT
Solve applications using the normal curve
100
rotal area
0.35
0.30-
0.25-
0.20-
0.15-
Probebility
0.10-
0.05
Area=0.16
91032-S 16 ripiA entot be9TA erli bniloT
10
a. What proportion of the population is between 4 and 6?
O. 16
67 P(4Lĕ E6) = 0.16 =16 7.
c. What proportion of the population is not between 4 and 6?
1-0.1b =0 84
owT neewte8 691A edt þai7 OT
6?
0.84
Tx=
The Normal Distribution
bell shaper
Symmearic
for POPUlationg that
2-Score i Ħ Of
Steindaro devaion
from the
Used
mean
A the distribution of a continuous variable.
Shade area under the curve and use Table A.2 to find the area/probability
b. If a value is at is the that it will be b
distributed
Transcribed Image Text:How many apps? According to a website, the mean number of apps on a smartphone in the United States is 90. Assume the number of apps is normally distributed with mean 90 and standard deviation 21. 6.1 The Normal Curve Convert nermativalues tojssCAresii bri7 oT Solve applications using the normal curve 100 rotal area 0.35 0.30- 0.25- 0.20- 0.15- Probebility 0.10- 0.05 Area=0.16 91032-S 16 ripiA entot be9TA erli bniloT 10 a. What proportion of the population is between 4 and 6? O. 16 67 P(4Lĕ E6) = 0.16 =16 7. c. What proportion of the population is not between 4 and 6? 1-0.1b =0 84 owT neewte8 691A edt þai7 OT 6? 0.84 Tx= The Normal Distribution bell shaper Symmearic for POPUlationg that 2-Score i Ħ Of Steindaro devaion from the Used mean A the distribution of a continuous variable. Shade area under the curve and use Table A.2 to find the area/probability b. If a value is at is the that it will be b distributed
Part 2 of 2
(b) Find the 70™ percentile of the number of apps. Round the answer to two decimal places.
The 70th percentile of the number of apps is.
Shade area unde
Convert normal value
Solve applications using
6.1 The N
Learning Objective
0.35-
Probability
0.30-
0.25-
0.20-
0.15-
Area=0.16
0.10-
0.05-
0-
What proportion of the population is between 4 and 67
0.16
b. If a value is chosen at random from this population, what is
62
P(4LX 56)=0.16 - 16%
AD
c. What proportion of the population is not between 4 and67
91'0-1
3D
084
d. If a value is chosen at random from this population, what
62
0.341
The Normal Distribution
147%
bell Shape
Simmentric
eo for PopUloーかns tr
2-Suore E
Sendord des
A probability density curve represents the prol
Fry
Transcribed Image Text:Part 2 of 2 (b) Find the 70™ percentile of the number of apps. Round the answer to two decimal places. The 70th percentile of the number of apps is. Shade area unde Convert normal value Solve applications using 6.1 The N Learning Objective 0.35- Probability 0.30- 0.25- 0.20- 0.15- Area=0.16 0.10- 0.05- 0- What proportion of the population is between 4 and 67 0.16 b. If a value is chosen at random from this population, what is 62 P(4LX 56)=0.16 - 16% AD c. What proportion of the population is not between 4 and67 91'0-1 3D 084 d. If a value is chosen at random from this population, what 62 0.341 The Normal Distribution 147% bell Shape Simmentric eo for PopUloーかns tr 2-Suore E Sendord des A probability density curve represents the prol Fry
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