Part 2 Materials A and B can both be described by the Drude-Lorentz-Sommerfeld Model. Their e as a function of frequency is shown below. By observing their e(w) profile as shown in the Figure below, choose the correct statements: real(epsilon) 64002 imag(epsilon) -10 0 0.5 0.5 Material A 1 Frequency Frequency (i) Wp.A> Wp.B. IA > IB (ii) Wp.A> Wp,B, IA IB (iv) wp.A
Part 2 Materials A and B can both be described by the Drude-Lorentz-Sommerfeld Model. Their e as a function of frequency is shown below. By observing their e(w) profile as shown in the Figure below, choose the correct statements: real(epsilon) 64002 imag(epsilon) -10 0 0.5 0.5 Material A 1 Frequency Frequency (i) Wp.A> Wp.B. IA > IB (ii) Wp.A> Wp,B, IA IB (iv) wp.A
Related questions
Question
Please asap

Transcribed Image Text:Part 2 Materials A and B can both be described by the Drude-Lorentz-Sommerfeld Model. Their e as a function
of frequency is shown below. By observing their e(w) profile as shown in the Figure below, choose the correct
statements:
real(epsilon)
imag(epsilon)
64202
O
-5
-10
0
0.5
0.5
Material A
1
Frequency
1
Frequency
(i) Wp.A> Wp.B, IA > FB
(ii) Wp.A> Wp.B, IA <IB
(iii) Wp,A<Wp, B, IA > IB
(iv) Wp,A<Wp,B, IA <TB
1.5
1.5
2
2
x(w) =
real(epsilon)
imag(epsilon)
8
0 50
LE
O
-50
-100
0
w²-jwr-w
0.5
0.5
Material B
1
Frequency
1
Frequency
1.5
1.5
2
2
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 5 images
