#33Part 1 of 4A college professor believes that students achieve a higher grade point average (GPA) in the fallsemester than in the spring semester. To test her theory, she samples 38 of her fall semesterstudents and 40 of her spring semester students. The fall semester students had an averagesemester GPA of 2.99 with a standard deviation of 0.45; the spring semester students had anaverage semester GPA of 2.92 with a standard deviation of 0.41. If the GPAs in both studentpopulations are normally distributed, conduct a hypothesis test using a 5% level of significance totest the professor's theory.EStep 1: State the null and alternative hypotheses. Let up indicate the mean GPA of fallsemester students and us indicate the mean GPA of spring semester students.Ho: ur – μs εννοHa: Fus(So we will be performing a right-tailedThe differences of sample means are t-distributedand distribution standard deviation 1Question Help: D Post to forumSubmit PartPart 2 of 4Step 2: Assuming the null hypothesis is true, determine the features of the distribution of thedifferences of sample means.$4Rtest.)%5TXG Search or type URL✔with distribution mean o6>&7▼LI* 0089

Answered: Image /qna-images/answer/09a159de-f6bc-4495-87b9-209c808a31fa.jpg

Answered: ▾ Part 1 of 4 A college professor…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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According to the U.S. Census, the average adult woman is the United States is 65 inches tall and the standard deviation is 3 inches. If Zsike is 67 inches tall, what is her z-score?
One year Terry had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitcher at his school, with an ERA of 3.02. Also, Karen had the lowest ERA of any female pitcher at the school with an ERA of 3.24. For the males, the mean ERA was 4.364 and the standard deviation was 0.639. For the females, the mean ERA was 3.801 and the standard deviation was 0.959 Find their respective z-scores. Which player had the better year relative to their peers, Terry or Karen? (Note: In general, the lower the ERA, the better the pitcher.) Terry had an ERA with a z-score of Karen had an ERA with a z-score of (Round to two decimal places as needed) Which player had a better year in comparison with their peers? OA. Terry had a better year because of a higher z-score. OB. Karen had a better year because of a lower z-score. OC. Terry had a better year because of a lower z-score. O D. Karen had a better year because of a higher z-score. GIL
The mean finish time for a yearly amateur auto race was 187.07 minutes with a standard deviation of 0.379 minute. The winning car, driven by Josh, finished in 186.08 minutes. The previous year's race had a mean finishing time of 112.9 with a standard deviation of 0.114 minute. The winning car that year, driven by Sally, finished in 112.67 minutes. Find their respective z-scores. Who had the more convincing victory? Josh had a finish time with a z-score of Sally had a finish time with a z-score of (Round to two decimal places as needed.)
Russell is doing some research before buying his first house. He is looking at two different areas of the city, and he wants to know if there is a significant difference between the mean prices of homes in the two areas. For the 39 homes he samples in the first area, the mean home price is $⁢176,400. Public records indicate that home prices in the first area have a population standard deviation of $⁢32,930. For the 32 homes he samples in the second area, the mean home price is $⁢181,500. Again, public records show that home prices in the second area have a population standard deviation of $⁢23,835. Let Population 1 be homes in the first area and Population 2 be homes in the second area. Construct a 95% confidence interval for the true difference between the mean home prices in the two areas. Round the endpoints of the interval to the nearest whole number, if necessary. Lowest Endpoint = upper Endpoint=
Loretta, who turns 91 this year, has heard that the mean systolic blood pressure among the elderly is 120 millimeters of mercury (mm Hg), but she believes that the actual value is higher. She bases her belief on a recently reported study of 19 randomly selected, elderly adults. The sample mean systolic blood pressure of the adults in the study was 121 mm Hg , and the sample standard deviation was 20 mm Hg. Assume that the population of systolic blood pressures of elderly adults is normally distributed. Based on the study, at the 0.1 level of significance, can it be concluded that μ , the mean systolic blood pressure among elderly adults, is greater than 120 mm Hg? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified in the table. (a) State the null hypothesis H0? and the alternative hypothesis H1? . H0:? H1:? (b) Determine the type of test statistic to…
A newspaper article reports that the mean cost for preventative dental care per year is $175 with a standard deviation of $35 (assume that this is the population standard deviation). You want to test whether the mean cost for preventative dental care in your company is different from what was reported in the article. You take a random sample of 250 employees and find the mean cost is $171. Does this signficantly differ from what was reported in the article? Run the appropriate test at α=0.05. Give each of the following to receive full credit: 1) the appropriate null and alternative hypotheses; 2) the appropriate test; 3) the decision rule; 4) the calculation of the test statistic; and 5) your conclusion including a comparison to alpha or the critical value. You MUST show your work to receive full credit. Partial credit is available.
▼ Part 1 of 4 Londell, an accomplished marathon runner, claims that the standard deviation for his time to run a 26.2 mile marathon is less than 11.1 minutes. To test his claim, Londell looks up 17 of his race times (in minutes): 238.6, 240, 231.4, 241.4, 251.9, 230.4, 232.1, 235.7, 234.6, 242.9, 240.5, 237.6, 242.2, 245.7, 235.7, 240.2, 233.9 Perform a hypothesis test using a 1% level of significance to test Londell's claim. Step 1: State the null and alternative hypotheses. Ho:o 11.1 Ha:o
A successful basketball player has a height of 6 feet 11 inches, or 211 cm. Based on statistics from a data set, his height converts to the z score of 5.17. How many standard deviations is his height above the mean?

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