Part 1 – Elastic collision (Elasticity 100%)Position 1 = 1m, position 2 = 2m (the distance between the two balls is 1 m)a) mi = m2 = 2kgPi = mi vli + m2 vzi = mi Vli + 0PE= mi vif + m2 v2f = 0+ m2 v2fV2i = 0Ki = (0.5 mi vli?) + (0.5 m2 v) = (0.5 mi vi?)+ 0Ki= (0.5 mi vir) + (0.5 m2 v) = 0 + (0.5 m2 v2r)Table 1ViiV2iVifV2fPi =Pf =PfPiKi =Kf =KfKi0.5mivi 0.5m2v2rmivlim2v2f(m/s) (m/s) (m/s) (m/s)(kg.m/s) (kg.m/s)(J)(J)2.002.503.00

In elastic collision momentum before collision=momentum after collision Kinetic energy before…

Part 1- Elastic collision (Elasticity 100%) Position 1 = 1m, position 2 = 2m (the distance between the two balls is 1 m) a) mi = m2 = 2kg Pi = mi vli + m2 Vi = mi vli+ 0 PE = mi vrf + m2 V2f = 0+ m2 vE V2i = 0 Ki = (0.5 mı vi) + (0.5 m2 vz) = (0.5 mi vi) + 0 Kf= (0.5 mi vir)+ (0.5 m2 v2r)= 0+ (0.5 m2 vr) Table 1 Vii V2i Vir Pi = Pf = PfPi Ki = Kf = Kf/Ki 0.5miv1? 0.5m2v2? mivi m2v2f (m/s) | (m/s) | (m/s) | (m/s) (kg.m/s) (kg.m/s) (J) (J) 2.00 2.50 3.00

Part 1- Elastic collision (Elasticity 100%) Position 1 = 1m, position 2 = 2m (the distance between the two balls is 1 m) a) mi = m2 = 2kg Pi = mi vli + m2 Vi = mi vli+ 0 PE = mi vrf + m2 V2f = 0+ m2 vE V2i = 0 Ki = (0.5 mı vi) + (0.5 m2 vz) = (0.5 mi vi) + 0 Kf= (0.5 mi vir)+ (0.5 m2 v2r)= 0+ (0.5 m2 vr) Table 1 Vii V2i Vir Pi = Pf = PfPi Ki = Kf = Kf/Ki 0.5miv1? 0.5m2v2? mivi m2v2f (m/s) | (m/s) | (m/s) | (m/s) (kg.m/s) (kg.m/s) (J) (J) 2.00 2.50 3.00

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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