Part 1: AHdissolution Trial 1 Trial 2 1201659 130.29 3.759 133.959 (calculated) 0.09399 (calculated) 125.22 30.2% 5c Mass of Water 5.154 125.864 (calculated) 0.6465 25.2c 36.2°6 Mass of NaOH Total Mass in cup (calculated) Mole of NaOH Initial Temperature Final Temperature Change in Temperature_ (calculated) (calculated) AHdissolution Average AHdissolution Accepted AHdissolution Percent Error Calculation of AHdissolution for trial 1 Part 2: AHneutralization Trial 1 Trial 2 58.65 Mass of 1.0 M HCI Vol. of 1.0 M HCI (calculated) (calculated) Vol. of 1.0 M NAOH 50ML 5TML Mass of 1.0 M NaOH (calculated) (calculated) Mole of HCI used (calculated) (calculated) Mole of NaOH used (calculated) (calculated) Total Mass in Calorimeter (calculated) (calculated) Initial Temperature NaOH 254 25.0°C 25.4'C 24.502 24.95 Initial Temperature HCI Average Initial Temperature 25'2

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Report Sheet --Heat of Reaction/Heat of Solution
Name
Part 1: AHdissolution
Trial 1
Trial 2
120659
130.29
3.754
133.959 (calculated)
0.09389 (calculated)
Mass of Water
Mass of NaOH
125.869(calculated)
0.6465
25.2c
36.2°6
Total Mass in cup
_(calculated)
Mole of NaOH
Initial Temperature 25.2C
30.2%
5c
Final Temperature
Change in Temperature_
(calculated)
(calculated)
AHdissolution
Average AHdissolution
Accepted AHdissolution
Percent Error
Calculation of AHdissolution for trial 1
Part 2: AHneutralization
Trial 1
Trial 2
54.84
58.65
Mass of 1.0 M HCI
Vol. of 1.0 M HCI
(calculated)
(calculated)
Vol. of 1.0 M NAOH50ML
55ML
Mass of 1.0 M NaOH
(calculated)
(calculated)
Mole of HCI used
(calculated)
(calculated)
Mole of NaOH used
(calculated)
(calculated)
Total Mass in Calorimeter
_(calculated)
(calculated)
Initial Temperature NaOH 25 4
25.0°%
25.4C
2450と
24.95
Initial Temperature HCI
Average Initial Temperature 25'2
Transcribed Image Text:Report Sheet --Heat of Reaction/Heat of Solution Name Part 1: AHdissolution Trial 1 Trial 2 120659 130.29 3.754 133.959 (calculated) 0.09389 (calculated) Mass of Water Mass of NaOH 125.869(calculated) 0.6465 25.2c 36.2°6 Total Mass in cup _(calculated) Mole of NaOH Initial Temperature 25.2C 30.2% 5c Final Temperature Change in Temperature_ (calculated) (calculated) AHdissolution Average AHdissolution Accepted AHdissolution Percent Error Calculation of AHdissolution for trial 1 Part 2: AHneutralization Trial 1 Trial 2 54.84 58.65 Mass of 1.0 M HCI Vol. of 1.0 M HCI (calculated) (calculated) Vol. of 1.0 M NAOH50ML 55ML Mass of 1.0 M NaOH (calculated) (calculated) Mole of HCI used (calculated) (calculated) Mole of NaOH used (calculated) (calculated) Total Mass in Calorimeter _(calculated) (calculated) Initial Temperature NaOH 25 4 25.0°% 25.4C 2450と 24.95 Initial Temperature HCI Average Initial Temperature 25'2
30.2
30.4°
5.45C
Final Temperature
Change in Temperature
A Hneutralization
Average AHneutralization
Accepted AHneutralization
Percent Error
Calculation of AHneutralization for Trial 1
Part 3: AHsys
Trial 1
Trial 2
61.304
Mass of 1.0 M HCI
1.50g
Mass of NaOH(s)
Mole of HCI
(calculated)
(calculated)
Mole of NaOH
(calculated)
(calculated)
Initial Temperature 25.1'C
32.1C
26.1C
34.2°C
Final Temperature
Change in Temperature F
AH system
Average AHsystem
Use Hess's Law to calculate AHdissolution indirectly
(Average AHsystem - Average AH neutralization)
Percent Difference: AHdissolution
(Part 1 and Part 3)
Transcribed Image Text:30.2 30.4° 5.45C Final Temperature Change in Temperature A Hneutralization Average AHneutralization Accepted AHneutralization Percent Error Calculation of AHneutralization for Trial 1 Part 3: AHsys Trial 1 Trial 2 61.304 Mass of 1.0 M HCI 1.50g Mass of NaOH(s) Mole of HCI (calculated) (calculated) Mole of NaOH (calculated) (calculated) Initial Temperature 25.1'C 32.1C 26.1C 34.2°C Final Temperature Change in Temperature F AH system Average AHsystem Use Hess's Law to calculate AHdissolution indirectly (Average AHsystem - Average AH neutralization) Percent Difference: AHdissolution (Part 1 and Part 3)
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