Part 1 After using the UT33B multimeter to check the voltage of the batteries and the resistance of, light bulb and resistors, these are the results: - Voltage of the battery is measured to be 1608 mV, The scale used to measure voltage is 2000mV on the UT33B multimeter - Resistance of the bulb is measured to be 0.24 ohm, The scale used to measure resistance is 200 ohm on the UT33B multimeter - Resistance of the resistor1 (R1) is measured to be 15.2 ohm, The scale used to measure resistance is 200 ohm on the UT33B multimeter - Resistance of the resistor2 (R2) is measured to be 27.2 ohm, The scale used to measure resistance is 200 ohm on the UT33B multimeter Part 2 After connecting a circuit to find the resistance of the light bulb and resistors experimentally using a circuit, these are the results: LIGHT BULB - Resistance of the light bulb and resistors could not be measured on the UT33B multimeter, so the voltage and current were measured and the resistance was found using ohms law. - Voltage of the light bulb is measured to be 1.421 V, The scale used to measure voltage is 2000mV on the UT33B multimeter. - Current of the light bulb is measured to be 1.3 A, The scale used to measure voltage is 200 mA on the UT33B multimeter. RESISTOR 1 - Voltage of resistor 1 is measured to be 1.464 V, The scale used to measure voltage is 2000mV on the UT33B multimeter. - Current of resistor 1 is measured to be 0.10 A, The scale used to measure voltage is 10 A on the UT33B multimeter. RESISTOR 2 - Voltage of resistor 2 is measured to be 1.512 V, The scale used to measure voltage is 2000mV on the UT33B multimeter. - Current of resistor 2 is measured to be 0.06 A, The scale used to measure voltage is 10 A on the UT33B multimeter. QUESTIONS i) find the resistance of the light bulb and resistors experimentally using a circuit. ii) Justify the scale used and quote the results in the standard form and hence determine the level of agreement between these measurements for Part 1 and Part 2.
Part 1
After using the UT33B multimeter to check the voltage of the batteries and the resistance of, light bulb and resistors, these are the results:
- Voltage of the battery is measured to be 1608 mV, The scale used to measure voltage is 2000mV on the UT33B multimeter
- Resistance of the bulb is measured to be 0.24 ohm, The scale used to measure resistance is 200 ohm on the UT33B multimeter
- Resistance of the resistor1 (R1) is measured to be 15.2 ohm, The scale used to measure resistance is 200 ohm on the UT33B multimeter
- Resistance of the resistor2 (R2) is measured to be 27.2 ohm, The scale used to measure resistance is 200 ohm on the UT33B multimeter
Part 2
After connecting a circuit to find the resistance of the light bulb and resistors experimentally using a circuit, these are the results:
LIGHT BULB
- Resistance of the light bulb and resistors could not be measured on the UT33B multimeter, so the voltage and current were measured and the resistance was found using ohms law.
- Voltage of the light bulb is measured to be 1.421 V, The scale used to measure voltage is 2000mV on the UT33B multimeter.
- Current of the light bulb is measured to be 1.3 A, The scale used to measure voltage is 200 mA on the UT33B multimeter.
RESISTOR 1
- Voltage of resistor 1 is measured to be 1.464 V, The scale used to measure voltage is 2000mV on the UT33B multimeter.
- Current of resistor 1 is measured to be 0.10 A, The scale used to measure voltage is 10 A on the UT33B multimeter.
RESISTOR 2
- Voltage of resistor 2 is measured to be 1.512 V, The scale used to measure voltage is 2000mV on the UT33B multimeter.
- Current of resistor 2 is measured to be 0.06 A, The scale used to measure voltage is 10 A on the UT33B multimeter.
QUESTIONS
i) find the resistance of the light bulb and resistors experimentally using a circuit.
ii) Justify the scale used and quote the results in the standard form and hence determine the level of agreement between these measurements for Part 1 and Part 2.
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