Part 1 (activity 1 picture) For the next activities, we will examine what happens when two blocks are placed in a fluid. We will use two blocks, block A (made of wood with density 0.40 kg/L), block B (also made of wood with density 0.40 kg/L) and block C (brick with density 2.0 kg/L). Each block will have a mass 4.4 kg (weight of each block = 44) N. In this activity, the fluid will be set to water with density 1 kg/L. The original volume of the fluid is 100 L. As show in Figure A. We start by placing Blocks A and C in the water with the brick placed on top of the wooden block.(See Figure B) The brick will float on top of the wooden block. In this situation (Figure B), the new volume of the fluid is 108.8 L. (1a) What is the buoyant force acting on the two block system in this case? The system is still in equilibrium and the sum of the forces must be equal to zero. Fbuoyant = _____ N (1b)What is the volume of fluid that is displaced when the blocks are placed in the water and the brick is floating on top of the ? Remember that the original volume of water in the container is 100 L. In order to determine the volume of the fluid that is displaced, you must look at the new volume of the fluid (Figure B) and subtract 100 L. Vfluid displaced = _____ L Since the brick is more dense the water, if we take the brick off of the wood block and place it in the water, it will sink. The question we would like to consider is what happens to amount of displaced water when the brick is placed in the water (and more specifically what happens to the water level in the container does it rise, stay the same level, or drop). (1c) Using the same blocks (Block A - wood, Block C - brick), we take the brick off of the wood and place it in the fluid so that it sinks (Figure C). In Figure C, the buoyant force acting on the wooden block (Block A) is equal to its weight since it is floating, FB1 = 44 N. On the other hand, the buoyant force acting on the brick is less than its weight since it sinks. In this case, FB2 = 22 N. The volume of the fluid in Figure C is measure to be VNew 2 = 106.6 L. (1c) What is the total buoyant force acting on both the wood block and the brick when the wood floats and the brick sinks? FB total = FB1 + FB2 = ______ N (1d) What is the volume of the fluid displaced under this condition? Remember that the original volume of water in the container is 100 L. In order to determine the volume of the fluid that is displaced, you must look at the volume of the fluid when the block is placed in the water and subtract 100 L. Vfluid displaced =_______ L Part 2 (activity 2 picture) For this activity, we start by placing Blocks A and B in the water with the one wooden block placed on top of the other wooden block.(See Figure B) Remember that each block has a mass of 4.4 kg (weight 44 N). The system floats. In this situation (Figure B), the new volume of the fluid is 108.8 L. (2a) What is the buoyant force acting on the two block system in this case? The system is still in equilibrium and the sum of the forces must be equal to zero. Fbuoyant = N (2b) What is the volume of fluid that is displaced when the blocks are placed in the water with one block floating on top of the other (Figure B)? Remember that the original volume of water in the container is 100 L. In order to determine the volume of the fluid that is displaced, you must use the new volume of the fluid when the blocks are placed in the water and subtract 100 L. Vfluid displaced = ____ L If we take the top wood block off of the lower wooden block and place it in the water, both wooden blocks will still float. The question we would like to consider is what happens to amount of displaced water when the top wooden block is placed in the water (and more specifically what happens to the water level in the container does it rise, stay the same level, or drop) (Figure C). We not that the buoyant force on each wooden block is FB1 = FB2 = 44 N. Additionally, the new volume of the fluid displaced is VNEW 2 = 108.8 L. (2c) What is the total buoyant force acting on both of the wooden blocks when both float separately? FB total = FB1 + FB2 = ____ N (2d) What is the volume of the fluid displaced under this condition? Remember that the original volume of water in the container is 100 L. In order to determine the volume of the fluid that is displaced, you must consider the volume of the fluid when the blocks are both floating in the water and subtract 100 L. Vfluid displaced = ___ L
Part 1 (activity 1 picture)
For the next activities, we will examine what happens when two blocks are placed in a fluid. We will use two blocks, block A (made of wood with density 0.40 kg/L), block B (also made of wood with density 0.40 kg/L) and block C (brick with density 2.0 kg/L). Each block will have a mass 4.4 kg (weight of each block = 44) N. In this activity, the fluid will be set to water with density 1 kg/L. The original volume of the fluid is 100 L. As show in Figure A.
We start by placing Blocks A and C in the water with the brick placed on top of the wooden block.(See Figure B) The brick will float on top of the wooden block. In this situation (Figure B), the new volume of the fluid is 108.8 L.
(1a) What is the buoyant force acting on the two block system in this case? The system is still in equilibrium and the sum of the forces must be equal to zero.
Fbuoyant = _____ N
(1b)What is the volume of fluid that is displaced when the blocks are placed in the water and the brick is floating on top of the ? Remember that the original volume of water in the container is 100 L. In order to determine the volume of the fluid that is displaced, you must look at the new volume of the fluid (Figure B) and subtract 100 L.
Vfluid displaced = _____ L
Since the brick is more dense the water, if we take the brick off of the wood block and place it in the water, it will sink. The question we would like to consider is what happens to amount of displaced water when the brick is placed in the water (and more specifically what happens to the water level in the container does it rise, stay the same level, or drop).
(1c) Using the same blocks (Block A - wood, Block C - brick), we take the brick off of the wood and place it in the fluid so that it sinks (Figure C). In Figure C, the buoyant force acting on the wooden block (Block A) is equal to its weight since it is floating, FB1 = 44 N. On the other hand, the buoyant force acting on the brick is less than its weight since it sinks. In this case, FB2 = 22 N. The volume of the fluid in Figure C is measure to be VNew 2 = 106.6 L.
(1c) What is the total buoyant force acting on both the wood block and the brick when the wood floats and the brick sinks?
FB total = FB1 + FB2 = ______ N
(1d) What is the volume of the fluid displaced under this condition? Remember that the original volume of water in the container is 100 L. In order to determine the volume of the fluid that is displaced, you must look at the volume of the fluid when the block is placed in the water and subtract 100 L.
Vfluid displaced =_______ L
Part 2 (activity 2 picture)
For this activity, we start by placing Blocks A and B in the water with the one wooden block placed on top of the other wooden block.(See Figure B) Remember that each block has a mass of 4.4 kg (weight 44 N). The system floats. In this situation (Figure B), the new volume of the fluid is 108.8 L.
(2a) What is the buoyant force acting on the two block system in this case? The system is still in equilibrium and the sum of the forces must be equal to zero.
Fbuoyant = N
(2b) What is the volume of fluid that is displaced when the blocks are placed in the water with one block floating on top of the other (Figure B)? Remember that the original volume of water in the container is 100 L. In order to determine the volume of the fluid that is displaced, you must use the new volume of the fluid when the blocks are placed in the water and subtract 100 L.
Vfluid displaced = ____ L
If we take the top wood block off of the lower wooden block and place it in the water, both wooden blocks will still float. The question we would like to consider is what happens to amount of displaced water when the top wooden block is placed in the water (and more specifically what happens to the water level in the container does it rise, stay the same level, or drop) (Figure C). We not that the buoyant force on each wooden block is FB1 = FB2 = 44 N. Additionally, the new volume of the fluid displaced is VNEW 2 = 108.8 L.
(2c) What is the total buoyant force acting on both of the wooden blocks when both float separately?
FB total = FB1 + FB2 = ____ N
(2d) What is the volume of the fluid displaced under this condition? Remember that the original volume of water in the container is 100 L. In order to determine the volume of the fluid that is displaced, you must consider the volume of the fluid when the blocks are both floating in the water and subtract 100 L.
Vfluid displaced = ___ L
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