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Part: 0/5 Part 1 of 5 The inequality is already in the formf(k) = 0. +2k-8 The expression is undefined for k = k+6

Part: 0/5 Part 1 of 5 The inequality is already in the formf(k) = 0. +2k-8 The expression is undefined for k = k+6

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Solve the Inequality:** Write the solution set in interval notation if possible. \[ \frac{k^2 + 2k - 8}{k + 6} \geq 0 \] **Part: 0 / 5** **Part 1 of 5** The inequality is already in the form \( f(k) \geq 0 \). The expression \(\frac{k^2 + 2k - 8}{k + 6}\) is undefined for \(k = \, \underline{\phantom{0}} \). --- **Explanation:** To solve this inequality, note that the expression is undefined when the denominator equals zero. Thus, find the value of \(k\) that makes \(k + 6 = 0\). This will indicate where the function is not defined.
Transcribed Image Text:**Solve the Inequality:** Write the solution set in interval notation if possible. \[ \frac{k^2 + 2k - 8}{k + 6} \geq 0 \] **Part: 0 / 5** **Part 1 of 5** The inequality is already in the form \( f(k) \geq 0 \). The expression \(\frac{k^2 + 2k - 8}{k + 6}\) is undefined for \(k = \, \underline{\phantom{0}} \). --- **Explanation:** To solve this inequality, note that the expression is undefined when the denominator equals zero. Thus, find the value of \(k\) that makes \(k + 6 = 0\). This will indicate where the function is not defined.
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