Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
![**Solve the Inequality:**
Write the solution set in interval notation if possible.
\[
\frac{k^2 + 2k - 8}{k + 6} \geq 0
\]
**Part: 0 / 5**
**Part 1 of 5**
The inequality is already in the form \( f(k) \geq 0 \).
The expression \(\frac{k^2 + 2k - 8}{k + 6}\) is undefined for \(k = \, \underline{\phantom{0}} \).
---
**Explanation:**
To solve this inequality, note that the expression is undefined when the denominator equals zero. Thus, find the value of \(k\) that makes \(k + 6 = 0\). This will indicate where the function is not defined.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F97e6de0b-6808-48e1-8e95-46529745f6f7%2F58423a99-5e44-47a1-96ea-a052be2a7687%2Fwo7muwc_processed.png&w=3840&q=75)
Transcribed Image Text:**Solve the Inequality:**
Write the solution set in interval notation if possible.
\[
\frac{k^2 + 2k - 8}{k + 6} \geq 0
\]
**Part: 0 / 5**
**Part 1 of 5**
The inequality is already in the form \( f(k) \geq 0 \).
The expression \(\frac{k^2 + 2k - 8}{k + 6}\) is undefined for \(k = \, \underline{\phantom{0}} \).
---
**Explanation:**
To solve this inequality, note that the expression is undefined when the denominator equals zero. Thus, find the value of \(k\) that makes \(k + 6 = 0\). This will indicate where the function is not defined.
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