Please answer question correctly pu-lgNslkr7j8P3jH-IB2.Moviegoers The average "moviegoer" sees 8.5 movies a year. A moviegoer is defined as a person who sees at least one movie inmovies seen per person was 8.9. The population standard deviation is 3.2 movies. At the 0.01 level of significance, can it beconcluded that this represents a difference from the national average?a theater in a 12-month period. A random sample of 50 moviegoers from a large university revealed that the average number ofPart: 0 /5Part 1 of 5State the hypotheses and identify the claim with the correct hypothesis.ロ>ロロ<ロ(Choose one) ▼H :(Choose one) ▼O=0ロチロThis hypothesis test is a (Choose one) v test.Part: 1/5Part 2 of 5Find the critical value(s). Round the answer to at least two decimal places. If there is more than one critical value, separatethem with commas.Critical value(s):Part: 2/5 Part 3 of 5Compute the test value. Always round z score values to at least two decimal places.Z=Part: 3/5Part 4 of 5Make the decision.(Choose one) v the null hypothesis.Part: 4 /5Part 5 of 5Summarize the results.There (Choose one) ▼ enough evidence to support the claim that the average number ofmovies seen by moviegoers from a large university is different from the national average.

Given : sample size, n = 50 sample mean, x̄ = 8.9 population standard deviation,σ=…

Part: 0/5 Part 1 of 5 State the hypotheses and identify the claim with the correct hypothesis. ロ<ロ Họ: (Choose one) ▼ O=0 ロロ H : (Choose one) V This hypothesis test is a (Choose one) test. Part: 1/5 Part 2 of 5 Find the critical value(s). Round the answer to at least two decimal places. If there is more than one critical valu them with commas. Critical value(s): Part: 2/5

Part: 0/5 Part 1 of 5 State the hypotheses and identify the claim with the correct hypothesis. ロ<ロ Họ: (Choose one) ▼ O=0 ロロ H : (Choose one) V This hypothesis test is a (Choose one) test. Part: 1/5 Part 2 of 5 Find the critical value(s). Round the answer to at least two decimal places. If there is more than one critical valu them with commas. Critical value(s): Part: 2/5

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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pu-lgNslkr7j8P3jH-IB2.
Moviegoers The average "moviegoer" sees 8.5 movies a year. A moviegoer is defined as a person who sees at least one movie in
movies seen per person was 8.9. The population standard deviation is 3.2 movies. At the 0.01 level of significance, can it be
concluded that this represents a difference from the national average?
a theater in a 12-month period. A random sample of 50 moviegoers from a large university revealed that the average number of
Part: 0 /5
Part 1 of 5
State the hypotheses and identify the claim with the correct hypothesis.
ロ>ロ
ロ<ロ
(Choose one) ▼
H :
(Choose one) ▼
O=0
ロチロ
This hypothesis test is a (Choose one) v test.
Part: 1/5
Part 2 of 5
Find the critical value(s). Round the answer to at least two decimal places. If there is more than one critical value, separate
them with commas.
Critical value(s):
Part: 2/5

Part 3 of 5
Compute the test value. Always round z score values to at least two decimal places.
Z=
Part: 3/5
Part 4 of 5
Make the decision.
(Choose one) v the null hypothesis.
Part: 4 /5
Part 5 of 5
Summarize the results.
There (Choose one) ▼ enough evidence to support the claim that the average number of
movies seen by moviegoers from a large university is different from the national average.

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