Parametric equation of a curve is given by : x = t³ – t y = t – 5t2 + 4 The equation of the tangent line at point where t = 0 is : y = 4 – x y = 4+x x = 0 y = 4
Parametric equation of a curve is given by : x = t³ – t y = t – 5t2 + 4 The equation of the tangent line at point where t = 0 is : y = 4 – x y = 4+x x = 0 y = 4
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Parametric equation of a curve is given by :
x = t³ – t
y = t – 5t2 +4
The equation of the tangent line at point where t = 0 is :
y = 4 – x
y = 4+ x
x = 0
y = 4
y = x – 4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F70562eea-c2fb-4751-9e42-c7c37c89fd29%2F07a6154e-25de-4f9c-b9a7-ffbf4b152b08%2Fb6j916_processed.png&w=3840&q=75)
Transcribed Image Text:Parametric equation of a curve is given by :
x = t³ – t
y = t – 5t2 +4
The equation of the tangent line at point where t = 0 is :
y = 4 – x
y = 4+ x
x = 0
y = 4
y = x – 4
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