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Parameters: A = 4 T= 2 Based on the provided numerical values, please find the convolution result for each of the five cases: (a) For t = 0, h(t)*x(t) = [ Select ] (b) For t = T/2, h(t)*x(t) = [ Select ] %3D (c) For t = T, h(t)*x(t) = [ Select ] d) For t = 3T/2, h(t)*x(t) = [ Select ] e) For t = 2T, h(t)*x(t) = [ Select ]

Parameters: A = 4 T= 2 Based on the provided numerical values, please find the convolution result for each of the five cases: (a) For t = 0, h(t)*x(t) = [ Select ] (b) For t = T/2, h(t)*x(t) = [ Select ] %3D (c) For t = T, h(t)*x(t) = [ Select ] d) For t = 3T/2, h(t)*x(t) = [ Select ] e) For t = 2T, h(t)*x(t) = [ Select ]

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Parameters: A = 4 T= 2 Based on the provided numerical values, please find the convolution result for each of the five cases: (a) For t = 0, h(t)*x(t) = [ Select ] (b) For t = T/2, h(t)*x(t) [ Select ] (c) For t = T, h(t)*x(t) = [ Select ] (d) For t = 3T/2, h(t)*x(t) [ Select ] (e) For t = 2T, h(t)*x(t) = [Select ]
Transcribed Image Text:Parameters: A = 4 T= 2 Based on the provided numerical values, please find the convolution result for each of the five cases: (a) For t = 0, h(t)*x(t) = [ Select ] (b) For t = T/2, h(t)*x(t) [ Select ] (c) For t = T, h(t)*x(t) = [ Select ] (d) For t = 3T/2, h(t)*x(t) [ Select ] (e) For t = 2T, h(t)*x(t) = [Select ]
Two rectangular pulses with amplitude A and pulse-width T are to be convolved by each other. h(t) x(1)| A A T h(t) * x(t) = [ h(1)x(t – A)d2 The graphical interpretation of the convolution integral has been illustrated below for five different values of t (the amount of time shift before multiplication and integration). (a) (b) x(t-X) h(a) x(t-) h() t = 0 t = T/2 -T+t -T+t (c) x(t-X) (d) x(t-A) h(a) h(a) t = T t = 3T/2 -Tft -T+t in. (e) x(t-A) h(A) t = 2T -T+t Parameters: A = 4 T = 2
Transcribed Image Text:Two rectangular pulses with amplitude A and pulse-width T are to be convolved by each other. h(t) x(1)| A A T h(t) * x(t) = [ h(1)x(t – A)d2 The graphical interpretation of the convolution integral has been illustrated below for five different values of t (the amount of time shift before multiplication and integration). (a) (b) x(t-X) h(a) x(t-) h() t = 0 t = T/2 -T+t -T+t (c) x(t-X) (d) x(t-A) h(a) h(a) t = T t = 3T/2 -Tft -T+t in. (e) x(t-A) h(A) t = 2T -T+t Parameters: A = 4 T = 2
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