Parallelogram ABCD with diagonals AC and BD is displayed. See Attachment, please. It is given that AC = BD. After proving that △BAD≅△ABC and △ADC≅△BCD, a teacher asks the students to prove that the parallelogram is a rectangle. Part of the proof is displayed, but two of the reasons are missing.See Attachment, please. Parallelogram ABCD with diagonals AC and BD is displayed.D.ABIt is given that AC = BD. After proving that ABAD=AABC and AADC = ABCD, a teacher asks the students to prove that the parallelogram is a rectangle. Part of the proof is displayed, but two of the reasons are missing.-- StatementReasonZBAD = ZABC, ZADC = ZBCDZBAD and ZABC are supplementaryY|ZADC and BCD are supplementarym/BAD+mZABC = 180°MZADC + MZBCD= 180°The sum of the measures of supplementary angles is 180°.MZBAD= MZABCMZADC = m/BCDm/BAD+m/BAD= 180MLADC+MZADC = 180°2m/BAD= 180°2MLADC = 180°m/BAD= 90°MZADC =90°ZBAD, ZABC, ZADC, and ZBCD are right angles Right angles have a measure of 90°Congruent angles are angles of equal measure.SubstitutionProperty of additionDivision property of equalityWhat are the missing reasons X and Y?X: Corresponding parts of congruent triangles are congruent.Y: If two parallel lines are cut by a transversal, the interior angles on the same side of the transversal are supplementary.X: Corresponding parts of congruent triangles are congruent.Y: If two parallel lines are cut by a transversal, the exterior angles on the same side of the transversal are supplementary.X: Consecutive angles of a parallelogram are congruent.Y: If two parallel lines are cut by a transversal, the interior angles on the same side of the transversal are supplementary.X: Consecutive angles of a parallelogram are congruent.Y: If two parallel lines are cut by a transversal, the exterior angles on the same side of the transversal are supplementary.

Name: Parallelogram ABCD with diagonals AC and BD is displayed. See Attac
Uploaded: 2024-03-20T06:47:08.000Z
Channel: Bartleby
Description: Parallelogram ABCD with diagonals AC and BD is displayed. See Attachment, please. It is given that AC = BD. After proving that △BAD≅△ABC and △ADC≅△BCD, a teacher asks the students to prove that the parallelogram is a rectangle. Part of the proof