Page | 8. Compute the velocity of light in Calcium Fluoride (CaF₂) which has Caielectric constant of 2.056 at frequencies within visible range range and magnetic susceptibility of -1-43 x 10-5.0 permeability of free space (Mo) = 4πT X10-7 H/m and permittivity of free space Space = 8.85 X 10²¹12² F/00
Page | 8. Compute the velocity of light in Calcium Fluoride (CaF₂) which has Caielectric constant of 2.056 at frequencies within visible range range and magnetic susceptibility of -1-43 x 10-5.0 permeability of free space (Mo) = 4πT X10-7 H/m and permittivity of free space Space = 8.85 X 10²¹12² F/00
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8. Compute the velocity of light in Calcium
Fluoride (CaF₂) which has Caielectric constant
of 2.056 at frequencies within visible range
range
and magnetic susceptibility of -1-43 x 10-5.0
permeability of free space (Mo) = 4πT X10-7 H/m
and permittivity of free
space = 8.85 ×10 ¹2 =F/on](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb5f2f2e5-15f7-449d-8038-5882b07b59d0%2Ffa1069f1-ba70-4caf-9481-b2f35494576c%2F5typt66_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Page |
8. Compute the velocity of light in Calcium
Fluoride (CaF₂) which has Caielectric constant
of 2.056 at frequencies within visible range
range
and magnetic susceptibility of -1-43 x 10-5.0
permeability of free space (Mo) = 4πT X10-7 H/m
and permittivity of free
space = 8.85 ×10 ¹2 =F/on
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