Page 426, Concept Problem 6.3.Solve thisproblem completely, but with the following changes (Note that itinvolves the Sample Problem 5.8 on Page 377) (1)Changethepoint-load from50 kN to35kN. Keep in mind thatthis change will result in many other changes across the board. Discuss all practical issues in your findings.Important: you must also show all your new intermediate results from Sample Problem 5.8. AA,A60 KN|--1.5m-|-1.5m-|-52 kN(67.6)Bx= 2.6 m50 KN1m 1mE B-8 kN-58 KNOXConcept Application 6.3Knowing that the allowable shearing stress for the steel beam of SampleProb. 5.8 is Tall = 90 MPa, check that the W360 x 32.9 shape obtainedis acceptable from the point of view of the shearing stresses.Recall from the shear diagram of Sample Prob. 5.8 that the max-imum absolute value of the shear in the beam is |V]max = 58 kN. Itmay be assumed that the entire shear load is carried by the web andthat the maximum value of the shearing stress in the beam can beobtained from Eq. (6.11). From Appendix E, for a W360 x 32.9 shape,the depth of the beam and the thickness of its web are d = 348 mmand t = 5.84 mm. Thus,Aweb dtw = (348 mm) (5.84 mm) = 2032 mm²Substituting Vmax and Aweb into Eq. (6.11),|VImax58 KNAweb2032 mm²Tmax== 28.5 MPaSince Tmax < Tall the design obtained in Sample Prob. 5.8 isacceptable. A5 lb9 in.Fig. P5.812 lb5 lbDV E12 in.9 in.5 lbB12 in.

A simply supported beam, with simple supports at A and D, is loaded with a UDL of 20kNm from A to B…

Answered: Page 426, Concept Problem 6.3.Solve…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Page 426, Concept Problem 6.3.Solve thisproblem completely, but with the following changes (Note that itinvolves the Sample Problem 5.8 on Page 377) (1)Changethepoint-load from50 kN to35kN. Keep in mind thatthis change will result in many other changes across the board. Discuss all practical issues in your findings.Important: you must also show all your new intermediate results from Sample Problem 5.8.

A
A,
A
60 KN
|--1.5m-|-1.5m-|-
52 kN
(67.6)
B
x= 2.6 m
50 KN
1m 1m
E B
-8 kN
-58 KN
O
X
Concept Application 6.3
Knowing that the allowable shearing stress for the steel beam of Sample
Prob. 5.8 is Tall = 90 MPa, check that the W360 x 32.9 shape obtained
is acceptable from the point of view of the shearing stresses.
Recall from the shear diagram of Sample Prob. 5.8 that the max-
imum absolute value of the shear in the beam is |V]max = 58 kN. It
may be assumed that the entire shear load is carried by the web and
that the maximum value of the shearing stress in the beam can be
obtained from Eq. (6.11). From Appendix E, for a W360 x 32.9 shape,
the depth of the beam and the thickness of its web are d = 348 mm
and t = 5.84 mm. Thus,
Aweb dtw = (348 mm) (5.84 mm) = 2032 mm²
Substituting Vmax and Aweb into Eq. (6.11),
|VImax
58 KN
Aweb
2032 mm²
Tmax=
= 28.5 MPa
Since Tmax < Tall the design obtained in Sample Prob. 5.8 is
acceptable.

A
5 lb
9 in.
Fig. P5.8
12 lb
5 lb
DV E
12 in.
9 in.
5 lb
B
12 in.

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