The second photo has the background information needed to solve the practice problem. Page 104 Practice Problem 4.4: If passenger comfort requires that the acceleration should beno greater in magnitude than 0.10g, what distance is required to stop the car if its speed isinitially 30m/s (roughly 60mi/h)? What force is required? Answers: 459m, 1960 N. EXAMPLE 4.4 Quick stop of a heavy carIn this example we consider a problem in which the weight of an object is given directly, but not its mass.To use Newton's second law, we will, of course, first have to determine the object's mass. A big luxury carweighing 1.96 X 104 N (about 4400 lb), traveling in the +x direction, makes a fast stop; the x componentof the net force acting on it is -1.50 X 104 N. What is its acceleration?OXOSOLUTIONSET UP Figure 4.19 shows our diagram. We draw the weight as a forcewith magnitude w. Because the car does not accelerate in the y direc-tion, the road exerts an upward normal force of equal magnitude on thecar; for completeness, we include that force in our diagram.SOLVE To find the acceleration, we'll use Newton's second law,EF= max. First, however, we need to find the car's mass. Sincewe know the car's weight, we can find its mass m from Equation 4.9,w = mg. We obtainm =MaryThen, EF, = ma, givesax=WDAD8Fx1.96 × 104 N9.80 m/s²m-1.50 × 104 N2000 kg== -7.5 m/s².Video Tutor Demo.1.96 x 104 kg m/s²9.80 m/s²= 2000 kg.20.-1.50 × 104 kg m/s²2000 kgāF = -1.50 x 104 NVideo Tutor Solutionn = 1.96 x 104 Neno morì 2917 155 do 10 1A FIGURE 4.19 Our diagram for this problem.W 1.96 x 10+ NREFLECT This acceleration can be written as -0.77g. Note that-0.77 is also the ratio of -1.50 X 104 N to 1.96 x 104 N. An accel-eration of this magnitude is possible only on a dry paved road. Don'texpect it on a wet or icy road!Practice Problem: If passenger comfort requires that the accelerationshould be no greater in magnitude than 0.10 g, what distance is requiredto stop the car if its speed is initially 30 m/s (roughly 60 mi/h)? Whatforce is required? Answers: 459 m, 1960 N.Usually, the easiest way to measure the mass of an object is to measure its weight, oftenby comparison with a standard weight. In accordance with Equation 4.10, two objects thathave the same weight at a particular location also have the same mass. We can compareweights very precisely: The familia

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Description: The second photo has the background information needed to solve the practice problem. Page 104 Practice Problem 4.4: If passenger comfort requires that the acceleration should beno greater in magnitude than 0.10g, what distance is required to stop th