pads/CHM%20111%20Empirical%20Formula%20.pdf D|A Mass of crucible and lid (g) 30 673 g Mass of crucible and lid (g) (optional second heating) Mass of crucible, lid and magnesium (g) 30.896 g Mass of magnesium (g) 0.223 g Description of color change of pH paper Changed from green to blue (pH 6 to 9) Mass of crucible, lid and product (g) 30.974 g Mass of crucible, lid and product (g) (optional second heating) alculate the mass of product (g). (show your calculation) 0.301 g 30.974 g-30.673 g 0.078 g ulculate the mass of oxygen (g) in the product. (show your calculation) 0.301g-0.223 g Iculate the mass percent of magnesium and oxygen in the product 74.1 % Mg 25.9 % O % mg= 0.223 g/0.301 g × 100 % = 74.1 % %0 = 0.078 g /0.301 g x 100 % = 25.9 % 0.0093 moles alculate the moles of magnesium (show your calculation) ua: mobs of magnesium molar moss of magnesum ven mass of magnesium = 0.223 g ple of magnesium = 0.223 g/ 24g/mol = 0.0093 moles lculate the moles of oxygen (O) in the product (show your calculation) at is the empirical formula of the compound? 7. Experiment: Empirical Formula
pads/CHM%20111%20Empirical%20Formula%20.pdf D|A Mass of crucible and lid (g) 30 673 g Mass of crucible and lid (g) (optional second heating) Mass of crucible, lid and magnesium (g) 30.896 g Mass of magnesium (g) 0.223 g Description of color change of pH paper Changed from green to blue (pH 6 to 9) Mass of crucible, lid and product (g) 30.974 g Mass of crucible, lid and product (g) (optional second heating) alculate the mass of product (g). (show your calculation) 0.301 g 30.974 g-30.673 g 0.078 g ulculate the mass of oxygen (g) in the product. (show your calculation) 0.301g-0.223 g Iculate the mass percent of magnesium and oxygen in the product 74.1 % Mg 25.9 % O % mg= 0.223 g/0.301 g × 100 % = 74.1 % %0 = 0.078 g /0.301 g x 100 % = 25.9 % 0.0093 moles alculate the moles of magnesium (show your calculation) ua: mobs of magnesium molar moss of magnesum ven mass of magnesium = 0.223 g ple of magnesium = 0.223 g/ 24g/mol = 0.0093 moles lculate the moles of oxygen (O) in the product (show your calculation) at is the empirical formula of the compound? 7. Experiment: Empirical Formula
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
11) calculate the moles of oxygen ( O) in the product (Show your calculation)
and what is the empirical formula of the compound ?
Transcribed Image Text:714/Downloads/CHM%20111%20Empirical%20Formula%20.pdf
D|A
T
1. Mass of crucible and lid (g)
30 673 g
2. Mass of crucible and lid (g) (optional second heating)
3. Mass of crucible, lid and magnesium (g)
30.896 g
4. Mass of magnesium (g)
0.223 g
Description of color change of pH paper
Changed from green to blue
(pH 6 to 9)
5. Mass of crucible, lid and product (g)
30.974 g
6. Mass of crucible, lid and product (g) (optional second heating)
7. Calculate the mass of product (g). (show your calculation)
0.301 g
30.974 g-30.673 g
8. Calculate the mass of oxygen (g) in the product. (show your calculation)
0.078 g
0.301g-0.223 g
9. Calculate the mass percent of magnesium and oxygen in the product
74.1
% Mg 25.9 %O
% mg= 0.223 g/0.301 g x 100 % = 74.1 %
%0 = 0.078 g /0.301 g x 100 % = 25.9 %
0.0093 moles
10. Calculate the moles of magnesium (show your calculation)
formua: moss of magnesium
molar mass of magnesum
Given mass of magnesium = 0.223 g
Mole of magnesium = 0.223 g/ 24g/mol = 0.0093 moles
11. Calculate the moles of oxygen (O) in the product (show your calculation)
12. What is the empirical formula of the compound?
Experiment: Empirical Formula
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