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P4(s)+5O2(g)⟶P4O10(s)                                ΔG°=−2697.0 kJ/mol 2H2(g)+O2(g)⟶2H2O(g)                               ΔG°=−457.18 kJ/mol 6H2O(g)+P4O10(s)⟶4H3PO4(l)                     ΔG°=−428.66 kJ/mol Net Equation: 3/2 H2 (g) + ¼ P4 (s) + 2 O2 (g) → H3PO4 (l)  Using Hess’s law to determine the standard free energy of formation, ΔG∘f, for phosphoric acid

P4(s)+5O2(g)⟶P4O10(s)                                ΔG°=−2697.0 kJ/mol 2H2(g)+O2(g)⟶2H2O(g)                               ΔG°=−457.18 kJ/mol 6H2O(g)+P4O10(s)⟶4H3PO4(l)                     ΔG°=−428.66 kJ/mol Net Equation: 3/2 H2 (g) + ¼ P4 (s) + 2 O2 (g) → H3PO4 (l)  Using Hess’s law to determine the standard free energy of formation, ΔG∘f, for phosphoric acid

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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  1. Given:

P4(s)+5O2(g)⟶P4O10(s)                                ΔG°=−2697.0 kJ/mol

2H2(g)+O2(g)⟶2H2O(g)                               ΔG°=−457.18 kJ/mol

6H2O(g)+P4O10(s)⟶4H3PO4(l)                     ΔG°=−428.66 kJ/mol

Net Equation: 3/2 H2 (g) + ¼ P4 (s) + 2 O2 (g) → H3PO4 (l)

 Using Hess’s law to determine the standard free energy of formation, ΔG∘f, for phosphoric acid.

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