π/4 x² dx (x²+4)5/2 0 (Use trigonometric substitution)

Q: r=2(9+1)sin0

A: Since  Sin (0) = 0

Q: 1 + tan² dx

A:

Q: sin x dx 4 3 Show that -

A: The integration can be written as;

Q: cosxdx 3T +Sinx

A:

Q: V2 sin(20) = – 2

A: Given that the equation is                                                     sin2θ=-22 we have to…

Q: sin 6xcos 3x dx

A:

Q: Sin X = 20 16 12

A:

Q: Sin 5

A:

Q: sqrt ((1+cos8x)/2) Use half angle formula cos(4x) cos(32x) cos(2x) cos(8x) cos(16x)

A:

Q: sin 3x dx 3-10cos3x 10.

A:

Q: sin 2x (1 - 2 cos 2x)? dx 6.

A:

Q: tan-13x dx 1 + 9x2

A:

Q: csch (2 sin2x)dx 1. 1– 4x²

A:

Q: sin3x dx 1+ tanx

A:

Q: Use a trigonometric substitution to calculate xVx² + 4 dx

A: Consider ∫x3x2+4dx, Take x=2tanθ, dx=2sec2θdθ So,…

Q: cot5 (VT-2x)csc³(VT-2x) dx 5 v1-2x

A: Given,         ∫cot51-2xcsc31-2x51-2xdx

Q: Se-²xsin(e-²x) dx е

A:

Q: sin?0 d0 4. S 1+ cose

A: The trigonometric identity, sin2x+cos2x=1 is true for every value of the occurring variables for…

Q: sečxdx ztanx 5-9tarix ansi sin 2

A: Solution is done in step 2

Q: [s sec³ x tan5 x dx

A: The given integral is sec3x tan5x.

Q: sinx find: - dx 3 cos2x +1

A: find ∫sinxcos2x+13 dx first lets simplify it and then find the integral

Q: Let  x = 4 sin θ, − π/2 < θ < π/2.  Simplify the expression.  x/sqrt(16-x^2)

A: x = μ sinθ   i - λ¯2 ∠θ ∠ λ¯2