P4 + 6H2 → 4PH3 R = k[H₂] What is the rate constant for the reaction given the rate law and data? Trial [P], (M) [H₂], (M) Initial Rate (M/s) 1 0.0220 0.0150 3.20 x 10-4 2 0.0220 0.0300 6.40 x 10-4 3 0.0440 0.0300 6.39 x 10-4 k = [?] Do not include units. Rate Constant Enter
P4 + 6H2 → 4PH3 R = k[H₂] What is the rate constant for the reaction given the rate law and data? Trial [P], (M) [H₂], (M) Initial Rate (M/s) 1 0.0220 0.0150 3.20 x 10-4 2 0.0220 0.0300 6.40 x 10-4 3 0.0440 0.0300 6.39 x 10-4 k = [?] Do not include units. Rate Constant Enter
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Chapter12: Kinetics
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Problem 31E: The following data have been determined for the reaction: I+OCIIO+CI 1 2 3 [I] 0.10 0.20 0.30 [OCI]...
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![P4 + 6H₂ → 4PH3
4PH3 R = k[H₂]
What is the rate constant for the reaction
given the rate law and data?
Trial [Palo (M) [H₂], (M) Initial Rate (M/s)
1
0.0220
0.0150
3.20 x 10-4
2
0.0220
0.0300
6.40 x 10-4
3
0.0440 0.0300
6.39 x 10-4
k = [?]
Do not include units.
Rate Constant
Enter](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6728fb77-e992-4bbe-bd2c-bb3e555269de%2F99e842c9-00ee-46d5-a797-a7eda502310b%2Fzx1hwq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:P4 + 6H₂ → 4PH3
4PH3 R = k[H₂]
What is the rate constant for the reaction
given the rate law and data?
Trial [Palo (M) [H₂], (M) Initial Rate (M/s)
1
0.0220
0.0150
3.20 x 10-4
2
0.0220
0.0300
6.40 x 10-4
3
0.0440 0.0300
6.39 x 10-4
k = [?]
Do not include units.
Rate Constant
Enter
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