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P2.1-1) The position of a particle moving along a straight line is given by x=(1/2)(br² +2ct+d) where is time and b, c and d are constants. Determine the particle's acceleration. Given: Find: Solution: Derive the particle's velocity. Circle the equation that you will use? "1 ds dr V= v(t)= Derive the particle's acceleration. Circle the equation that you will use? ds dr dv dr a(t) = ads=vdv dv dr ads=v dv

P2.1-1) The position of a particle moving along a straight line is given by x=(1/2)(br² +2ct+d) where is time and b, c and d are constants. Determine the particle's acceleration. Given: Find: Solution: Derive the particle's velocity. Circle the equation that you will use? "1 ds dr V= v(t)= Derive the particle's acceleration. Circle the equation that you will use? ds dr dv dr a(t) = ads=vdv dv dr ads=v dv

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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P2.1-1) The position of a particle moving along a straight line is given by x=(1/2)(br² +2ct+d) where is time and b, c and d are constants. Determine the particle's acceleration. Given: Find: Solution: Derive the particle's velocity. Circle the equation that you will use? "1 ds dr V= v(t)= Derive the particle's acceleration. Circle the equation that you will use? ds dr dv dr a(t) = ads=vdv dv dr ads=v dv
Transcribed Image Text:P2.1-1) The position of a particle moving along a straight line is given by x=(1/2)(br² +2ct+d) where is time and b, c and d are constants. Determine the particle's acceleration. Given: Find: Solution: Derive the particle's velocity. Circle the equation that you will use? "1 ds dr V= v(t)= Derive the particle's acceleration. Circle the equation that you will use? ds dr dv dr a(t) = ads=vdv dv dr ads=v dv
P2.1-2) The position of a particle moving along a straight line is given by s(t)=bcos(dt+c), where is time and b, c and d are constants. Determine the particle's velocity and acceleration as functions of time and the constants b, c and d. Also, find the maximum velocity of the particle. Given: Find: Solution: Derive the particle's velocity. Circle the equation that you will use? ds dt V= v(t) Derive the particle's acceleration. Circle the equation that you will use? dv dr ds di dv dr a= ads=vdv ads=vdv a(t)= Determine the particle's maximum velocity. What is the particle's acceleration when the velocity is maximum? Circle the correct answer. a = maximum, a = 0, a = minimum Determine the time at which the velocity reaches its maximum value.
Transcribed Image Text:P2.1-2) The position of a particle moving along a straight line is given by s(t)=bcos(dt+c), where is time and b, c and d are constants. Determine the particle's velocity and acceleration as functions of time and the constants b, c and d. Also, find the maximum velocity of the particle. Given: Find: Solution: Derive the particle's velocity. Circle the equation that you will use? ds dt V= v(t) Derive the particle's acceleration. Circle the equation that you will use? dv dr ds di dv dr a= ads=vdv ads=vdv a(t)= Determine the particle's maximum velocity. What is the particle's acceleration when the velocity is maximum? Circle the correct answer. a = maximum, a = 0, a = minimum Determine the time at which the velocity reaches its maximum value.
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