P2.1-1) The position of a particle moving along a straight line is given by x=(1/2)(br² +2ct+d) where is time and b, c and d are constants. Determine the particle's acceleration. Given: Find: Solution: Derive the particle's velocity. Circle the equation that you will use? "1 ds dr V= v(t)= Derive the particle's acceleration. Circle the equation that you will use? ds dr dv dr a(t) = ads=vdv dv dr ads=v dv

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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P2.1-1) The position of a particle moving along a straight line is given by x=(1/2)(br² +2ct+d)
where is time and b, c and d are constants. Determine the particle's acceleration.
Given:
Find:
Solution:
Derive the particle's velocity.
Circle the equation that you will use?
"1
ds
dr
V=
v(t)=
Derive the particle's acceleration.
Circle the equation that you will use?
ds
dr
dv
dr
a(t) =
ads=vdv
dv
dr
ads=v dv
Transcribed Image Text:P2.1-1) The position of a particle moving along a straight line is given by x=(1/2)(br² +2ct+d) where is time and b, c and d are constants. Determine the particle's acceleration. Given: Find: Solution: Derive the particle's velocity. Circle the equation that you will use? "1 ds dr V= v(t)= Derive the particle's acceleration. Circle the equation that you will use? ds dr dv dr a(t) = ads=vdv dv dr ads=v dv
P2.1-2) The position of a particle moving along a straight line is given by s(t)=bcos(dt+c), where
is time and b, c and d are constants. Determine the particle's velocity and acceleration as
functions of time and the constants b, c and d. Also, find the maximum velocity of the particle.
Given:
Find:
Solution:
Derive the particle's velocity.
Circle the equation that you will use?
ds
dt
V=
v(t)
Derive the particle's acceleration.
Circle the equation that you will use?
dv
dr
ds
di
dv
dr
a=
ads=vdv
ads=vdv
a(t)=
Determine the particle's maximum
velocity.
What is the particle's acceleration when the
velocity is maximum? Circle the correct
answer.
a = maximum, a = 0, a = minimum
Determine the time at which the velocity
reaches its maximum value.
Transcribed Image Text:P2.1-2) The position of a particle moving along a straight line is given by s(t)=bcos(dt+c), where is time and b, c and d are constants. Determine the particle's velocity and acceleration as functions of time and the constants b, c and d. Also, find the maximum velocity of the particle. Given: Find: Solution: Derive the particle's velocity. Circle the equation that you will use? ds dt V= v(t) Derive the particle's acceleration. Circle the equation that you will use? dv dr ds di dv dr a= ads=vdv ads=vdv a(t)= Determine the particle's maximum velocity. What is the particle's acceleration when the velocity is maximum? Circle the correct answer. a = maximum, a = 0, a = minimum Determine the time at which the velocity reaches its maximum value.
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