P14 Considering an undamped, forced oscillator (b = 0), show that Equation 15.35 is a solution of Equation 15.34 with an amplitude given by Equation 15.36. Equation 15.34: Fo sin(wt) – b – kæ = m d2x dt2 Equation 15.35: x = A cos(wt + o) () Fo m Equation 15.36: A = bw m

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Considering an undamped, forced oscillator (b = 0), show that Equation 15.35 is a solution of
Equation 15.34 with an amplitude given by Equation 15.36.

P14 Considering an undamped, forced oscillator (b = 0), show that Equation 15.35 is a solution of
Equation 15.34 with an amplitude given by Equation 15.36.
Equation 15.34: Fo sin(wt) – b – ka
d?x
m
Equation 15.35: x
A cos(wt + ø)
()
Fo
m
Equation 15.36: A =
bw
m
Transcribed Image Text:P14 Considering an undamped, forced oscillator (b = 0), show that Equation 15.35 is a solution of Equation 15.34 with an amplitude given by Equation 15.36. Equation 15.34: Fo sin(wt) – b – ka d?x m Equation 15.35: x A cos(wt + ø) () Fo m Equation 15.36: A = bw m
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