p(1, 1) = 0.25 p(2, 1) = 0.1 p(3, 1) = 0.1 P(XY = 2) P( \ > 1) = p(1, 2) = 0.05 p(2, 2) = 0.15 p(3, 2) = 0.1 a) Compute the conditional mass function of Y given X = 1: P(Y = 1|X = 1) = P(Y = 2|X = 1) = P(Y = 3|X = 1) = b) Are X and Y independent? (enter YES or NO) c) Compute the following probabilities: P(X + Y > 2) = = p(1, 3) = 0.05 p(2,3) = 0.1 p(3, 3) = 0.1
p(1, 1) = 0.25 p(2, 1) = 0.1 p(3, 1) = 0.1 P(XY = 2) P( \ > 1) = p(1, 2) = 0.05 p(2, 2) = 0.15 p(3, 2) = 0.1 a) Compute the conditional mass function of Y given X = 1: P(Y = 1|X = 1) = P(Y = 2|X = 1) = P(Y = 3|X = 1) = b) Are X and Y independent? (enter YES or NO) c) Compute the following probabilities: P(X + Y > 2) = = p(1, 3) = 0.05 p(2,3) = 0.1 p(3, 3) = 0.1
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcribed Image Text:The joint probability mass function of X and Y is given by
p(1, 1) = 0.25
p(1,2) = 0.05 p(1,3)
0.05
p(2, 1) = 0.1
p(2, 2) = 0.15
p(2, 3) = 0.1
p(3, 1) = 0.1
p(3, 2) = 0.1 p(3, 3) = 0.1
(a) Compute the conditional mass function of Y given X = 1:
P(Y = 1|X = 1) =
P(Y = 2|X = 1) =
P(Y = 3|X = 1) =
(b) Are X and Y independent? (enter YES or NO)
(c) Compute the following probabilities:
P(X + Y > 2) =
=
P(XY = 2) =
=
P(₹ > 1) =
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