P(0.97 <2<2.34) = Xx 5

Q: n=9,p=0.3x<3

A: Given: A binomial trial with n=9, p=0.3. The probability of binomial experiment is given as…

Q: Find P(2.03 < z < 4)= a. 0.979 b. 85.66 c. 1.645 d. 0.021

A: To find: Find P(2.03 &lt; z &lt; 4)= ?

Q: (Z over 8) - (1 over 2) = (z over 6)

A: Given equation is

Q: Assume P(Z>b)=0.22 for some number b. Without finding the value of b, what is P(Z<-b)?

A: From the provided information,P (Z&gt;b) = 0.22

Q: Find P(Z < 2.84)     .5375     .9575     .8098     .9977

A:

Q: Calculate P (-0.1 < Z < 0.1). (Round to the hundredths).

A:

Q: Find P(-1.40 < Z < 0)     .4192     .1259     .4357     .8907

A: Solution: Let Z be the standard normal random variable with mean μ=0 and standard deviation σ=1…

Q: P(z< ( Or equal to ) z0) = 0.7054

A:

Q: P(z>-1.80)=

A: Given : z=-1.80

Q: 0.13+15.04(x+3)=0.14+15.54

A: x=-1.96 Explanation is given below

Q: Assume P(Z> b) = 0.35 for some number b. Without finding the value of b, what P(Z < – b)?

A:

Q: P(x < 17.872)

A: Let's take the given  Sample size n=33 from a population, with mean=16 and standard deviation=8.4…

Q: P(0.68<:<2.18):

A: Z~N(0,1) To find:

Q: p(-2.75<z<-0.49)

A: Given that z is standard normal random variable:

Q: P(−1.14 ≤ z ≤ 2.63)

A: Let Z be the random variable from normal distribution then we will find the probability P(−1.14 ≤ z…

Q: P(1.15 < Z < 2.77) =

A: X~N( 0 , 1 )   μ=0 , ?=1 (for standard normal distribution)   Z-score =( x - μ )/?

Q: p(-c<z<c)=0.9464

A: P(-c&lt;z&lt;c)=0.9464

Q: n=10,p=0.3,x<4

A: The formula for binomial probability is represented as :   Given: n=10 p=0.3 x&lt; 4

Q: n=9, p=0.2x<3

A: Here we need to find P(X&lt;3).

Q: Let X represent the difference between the number of heads and the number of tails when a coin is…

A: Given that: Total number of times a coin tossed, n=36 To find: Probability of getting the difference…

Q: P ( -2.53 &lt; z &lt; 0.65)

A: The probability is,

Q: Find  ? such that ?(?<?<0)=0.4175

A: P(c&lt;Z&lt;0)=0.4175 c=?

Q: 57-x =1/125

A: