P(0.97 <2<2.34) = Xx 5

Q: n=9,p=0.3x<3

A: Given: A binomial trial with n=9, p=0.3. The probability of binomial experiment is given as…

Q: -0.73-0 /square root1-0.53/8 =

A: The objective of the question is to simplify the given mathematical expression.

Q: P=( 14,000 x 0.014+1/2 x 0.00238 x 51.332 x 0.412 x 34.3) x 51.33

A: we have given that  some operation + ,× , /

Q: lim exp(-nz)r'dr= 1. 2.0 3.

A: The solution is given as

Q: Find P(1.73< Z < 2.16)     a. 0.4334 b. 0.0263 c. 0.02641 d. 0.9428

A:

Q: Assume P(Z>b)=0.22 for some number b. Without finding the value of b, what is P(Z<-b)?

A: From the provided information,P (Z&gt;b) = 0.22

Q: Find P(Z < 2.84)     .5375     .9575     .8098     .9977

A:

Q: What is P( -1.03 < Z < 0.57 )?

A: The question is about standard normal distribution Introduction : Standard normal distribution. Z is…

Q: If 0.03 x = 70 then x = %3D %3D

A: detailed solution is given below

Q: P(z>-1.80)=

A: Given : z=-1.80

Q: 0.13+15.04(x+3)=0.14+15.54

A: x=-1.96 Explanation is given below

Q: P(-1.69 < z < 1.14) = %D

A: P(-1.69&lt;Z&lt;1.14) is given.

Q: find the derivative 343xt5

A: Recall the following. fx=ghxddxfx=ddxgxddxhx

Q: If 0.09 x = 90 then x =

A: 0.09 x = 90

Q: Find P (z > 2.59)

A: We have to find  P (z &gt; 2.59) = ?

Q: P(0.68<:<2.18):

A: Z~N(0,1) To find:

Q: p(-2.75<z<-0.49)

A: Given that z is standard normal random variable:

Q: P(−1.14 ≤ z ≤ 2.63)

A: Let Z be the random variable from normal distribution then we will find the probability P(−1.14 ≤ z…

Q: 5.355-1 +=+=+=8₁x²2² + + x³² 9.81x2 Find X from calculation

A:

Q: how to slove x over 5 =-7

A: 'x' over 'y' means 'x' divided by 'y' . i.e, xy.

Q: S S dydz = %3D

A:

Q: n=10,p=0.3,x<4

A: The formula for binomial probability is represented as :   Given: n=10 p=0.3 x&lt; 4

Q: [$3.50 × [1 + (– .122)]]/[.14 – (– .122)] = ?

A:

Q: the

A: Please refer to the image below

Q: Find P(1.73< Z < 2.16)

A:

Q: p re)=** equals ? -1/2

A:

Q: 54 B E D. C measure of <A =

A:

Q: Find P (-0. 55 < z < 2.51)

A:

Q: fond the Coefficient Ef e in The for//<1 |-20 per 17/2/199- to wanadda t4

A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…

Q: 3/2 lm Q=1.84 8-0.2| 263.67mm× lm 263.67 mm×- 1000 mm 1000 mm

A:

Q: x/2.625 +x/4.875 =1

A: Given equation is,

Q: P(Z < 0.58) = %3D 0. J0.2 J0.8 0.28 0.72

A: Given that, P(Z&lt;0.58)

Q: 0.2 0.4 0.6 0.6 1 f(x) 32 24 12 8. 10

A: Here we have to compute L5 using the given values.

Q: n=9, p=0.2x<3

A: Here we need to find P(X&lt;3).

Q: Find z1: 1. P(z1<z<2.98)=.1117

A:

Q: (9.35 × 10°) (7.47 × 10°) = 6.80 × 10 3.89 x 10-4 – 7.47 × 105 9.35 x 10°) (7.35 × 10° 2.42 х 10

A: Explanation and solution is given below....

Q: Find P (1.23 <z <2.35)

A:

Q: P ( -2.53 &lt; z &lt; 0.65)

A: The probability is,

Q: Find  ? such that ?(?<?<0)=0.4175

A: P(c&lt;Z&lt;0)=0.4175 c=?

Q: 57-x =1/125

A:

Q: 2.056 2[1.5]* 0.4525 750 0201 =

A: The given equation is We have to find the single unknown x.

Q: P(35<x<37) still 50 murders still 0.61 cleared

A:

Q: Evaluate In(0.473). Give your answer to four decimal places.

A: