Answered: p-0.2, 03 -0.2 P(p2 0.3) = P 0.067…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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I am confused. I do not understand how they got 0.0681 when using the standard normal Z table for 1.49. According to my table, that is for -1.49, and positive 1.49 has a z-score of 0.9319. Using the normalcdf function on my calculator, I can only get that result if I set 1.49 as my lower bounds and 10^99 as my upper bounds. Is this question asking for a right or left area? I thought the area to the left was supposed to be negative.

p-0.2, 03 -0.2
P(p2 0.3) = P
0.067
0.067
=P(z>149)
Using the standard normal table, we have:
P(p2 0.3) = P(z>1.49) = 0.0681
Since the P(p20.3) >0.05, therefore, it would not be suprising
that the player has a 0.3 average after 36 at-bats.

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