P.6-40 Find the mutual inductance between two coplanar rectangular loops with parallel sides, as shown in Fig. 6-50. Assume that hi >> h2 (h2 > w2 > d). Solution: Approximate the magnetic flux due to the long loop linking with the small loop by that due to two infinitely long wires carrying equal and opposite current I. hi h2 w, +dw, +d 1 dx d +x w, +d +x) A2 -In 27 Jo 27 d W; + w, +d d w2 A12 - 4h2 n (w, + d)(w; + d) L2 = %3D (p+m+!m)p Fig. 6-50
P.6-40 Find the mutual inductance between two coplanar rectangular loops with parallel sides, as shown in Fig. 6-50. Assume that hi >> h2 (h2 > w2 > d). Solution: Approximate the magnetic flux due to the long loop linking with the small loop by that due to two infinitely long wires carrying equal and opposite current I. hi h2 w, +dw, +d 1 dx d +x w, +d +x) A2 -In 27 Jo 27 d W; + w, +d d w2 A12 - 4h2 n (w, + d)(w; + d) L2 = %3D (p+m+!m)p Fig. 6-50
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Transcribed Image Text:P.6-40 Find the mutual inductance between two coplanar rectangular loops with parallel sides, as
shown in Fig. 6-50. Assume that hi >> h2 (h2> w2 > d).
Solution:
Approximate the magnetic flux due to the long loop linking with
the small loop by that due to two infinitely long wires carrying
equal and opposite current I.
hi
w, +dw +d
Hoh,I
A12
2л о
Hh,I
dx
d +x w, +d +x,
-In
d
W; + w, +d
A12- H,h, , (w, +d{w; +d)
d w2
In
%3D
2л
d(w, + w, +d)
Fig. 6-50
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