⇒ P X-μ O √n .25o 0 √n - P(2 < (+7)). ⇒PZ< = 0.95 = 0.95, since X - μ = Z O √n From a standard normal table, we then know that Z = 1.96
⇒ P X-μ O √n .25o 0 √n - P(2 < (+7)). ⇒PZ< = 0.95 = 0.95, since X - μ = Z O √n From a standard normal table, we then know that Z = 1.96
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Please explain throgouhly how do we get z=1.96
![⇒ P
Χ - μ
O
√n
.25o
0
- (²<(~7))-
(VF)
⇒PZ<
4
= 0.95
X - μ
O
√n
From a standard normal table, we then know that Z = 1.96
= 0.95, since
= Z](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9f8a9929-f352-418e-bc16-e81e7001bc4d%2Fd309d527-852b-4bab-b10a-a172aa638066%2F4c2llw8_processed.png&w=3840&q=75)
Transcribed Image Text:⇒ P
Χ - μ
O
√n
.25o
0
- (²<(~7))-
(VF)
⇒PZ<
4
= 0.95
X - μ
O
√n
From a standard normal table, we then know that Z = 1.96
= 0.95, since
= Z
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