⇒ P X-μ O √n .25o 0 √n - P(2 < (+7)). ⇒PZ< = 0.95 = 0.95, since X - μ = Z O √n From a standard normal table, we then know that Z = 1.96

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Please explain throgouhly how do we get z=1.96

⇒ P
Χ - μ
O
√n
.25o
0
- (²<(~7))-
(VF)
⇒PZ<
4
= 0.95
X - μ
O
√n
From a standard normal table, we then know that Z = 1.96
= 0.95, since
= Z
Transcribed Image Text:⇒ P Χ - μ O √n .25o 0 - (²<(~7))- (VF) ⇒PZ< 4 = 0.95 X - μ O √n From a standard normal table, we then know that Z = 1.96 = 0.95, since = Z
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