As part of a study designed to compare hybrid and similarly equipped conventional vehicles, a group tested a variety of classes of hybrid and all-gas model cars and sport utility vehicles (SUVS). Supposethe following data show the miles-per-gallon rating obtained for two hybrid small cars, two hybrid midsize cars, two hybrid small SUVS, and two hybrid midsize SUVS; also shown are the miles per gallonobtained for eight similarly equipped conventional models.ClassТуреMPGSmall CarHybrid38Small CarConventional27Small CarHybrid45Small CarConventional31Midsize CarHybrid27Midsize CarConventional23Midsize CarHybrid32Midsize CarConventional25Small SUVHybrid27Small SUVConventional21Small SUVHybrid28Small SUVConventional22Midsize SUVHybrid22Midsize SUVConventional20Midsize SUVHybrid23Midsize SUVConventional19At the a = 0.05 level of significance, test for significant effects due to class, type, and interaction.Find the value of the test statistic for class. (Round your answer to two decimal places.)Find the p-value for class. (Round your answer to three decimal places.) p-valueState your conclusion about class.Because the p-value < a = 0.05, class is significant.Because the p-value < a = 0.05, class is not significant.Because the p-value > a = 0.05, class is not significant.Because the p-value > a = 0.05, class is significant.Find the value of the test statistic for type. (Round your answer to two decimal places.)Find the p-value for type. (Round your answer to three decimal places.)p-valueState your conclusion about type.Because the p-value < a = 0.05, type is significant.Because the p-value > a = 0.05, type is significant.Because the p-value > a = 0.05, type is not significant.Because the p-value < a = 0.05, type is not significant.Find the value of the test statistic for interaction between class and type. (Round your answer to two decimal places.)Find the p-value for interaction between class and type. (Round your answer to three decimal places.)p-value =State your conclusion about interaction between class and type.Because the p-value > a = 0.05, interaction between class and type is significant.Because the p-value < a = 0.05, interaction between class and type is not significant.Because the p-value < a = 0.05, interaction between class and type is significant.Because the p-value > a = 0.05, interaction between class and type is not significant.O O 0 0O O O OO O O O

Given 2 way ANOVA with interaction factor A small midsize SUV midsize SUV…

p-value = State your conclusion about class. O Because the p-value < a = 0.05, class is significant. Because the p-value < a = 0.05, class is not significant. Because the p-value > a = 0.05, class is not significant. Because the p-value > a = 0.05, class is significant. Find the value of the test statistic for type. (Round your answer to two decimal places.) Find the p-value for type. (Round your answer to three decimal places.) p-value = State your conclusion about type. Because the p-value < a = 0.05, type is significant.

p-value = State your conclusion about class. O Because the p-value < a = 0.05, class is significant. Because the p-value < a = 0.05, class is not significant. Because the p-value > a = 0.05, class is not significant. Because the p-value > a = 0.05, class is significant. Find the value of the test statistic for type. (Round your answer to two decimal places.) Find the p-value for type. (Round your answer to three decimal places.) p-value = State your conclusion about type. Because the p-value < a = 0.05, type is significant.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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