P₂ V2 LV² V² 2g P1 ·+ α₁ pg +92 29 + Z₂ +htarbinç +hx,toplam hk,sürekli= f. 2g pg W mil pgỲH 01/2 Nsp hx,yeret = [Kk- hk toplam hk,sürekli + hk yerel npompa (gH)3/4 2g 1/2 wwmil VB VA ()* W _ P (~)*()* # - (-)*)* HB НА WmilA PA Wmil = pgHvntürbin Nst = p¹/2 (gH)5/4 Wmil = prwv(V₁-rw) (1 - cosß) At the best efficiency point with the experiments on the A turbine DA= 72 cm, HA= 20 m, A = 50 m³/s, PA= 998 kg/m³, nA= 205 revolution per minute, WmilA=9 MW values have been obtained. PB= 998 kg/m³, HB= 65 m, n= 185 A new B turbine will be designed. According to this; a) B is the volumetric flow of the turbine (VB) (m³/s) find as. c) Find the specific speed of turbine B. b) Find the power of turbine B. (Wmil.B) 2,5 285 245.3 MW 361 2.8 211,5 MW 180 2,1 190 MW 255 3,1 182,7 MW 375 250 MW - +Z₁ + hpompa.f V² d) Find the diameter of turbine B. 120 cm 156 cm 144 cm 104 cm 95 cm

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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Problem 1.1MA
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P1
+ a1
2g
P2
L V?
+z2 + hrarbing + hg,toplam hx,sürekli=f•5•2g
2g
+z + hpompa.f
+ az7
pg
pg
hk.yerel
hỵ,toplam= hx,sûrekli + hxyerel
Wmil
Nsp
2g
Протра
(gH)3/4
一()-)图)第-(m)G)
1/2
mil
WB (DB
WA DA
Wmil.B
(DB
(DB
Wmil = pgHỳntürbin
ww,
p1/2(gH)5/4
PB (WB
HB
WB
WmilA PA wa)
HA
Nst
Wmil = prwv(V; – rw)(1 – cosß)
%3D
At the best efficiency point with the experiments on the A turbine DA= 72 cm, Ha= 20 m, VA = 50 m³/s,
PA= 998 kg/m3, na= 205 revolution per minute, Wmila= 9 MW values have been obtained.
PB= 998 kg/m3, HB= 65 m, nB= 185 A new B turbine will be designed.
According to this;
a) B is the volumetric flow of the turbine (VB) (m/s) find as.
c) Find the specific speed of turbine B.
b) Find the power of turbine B. (Wmil.B)|
2,5
285
d) Find the diameter of turbine B.
245.3 MW
35
120 cm
361
211,5 MW
2.8
156 cm
180
190 MW
2,1
144 crm
255
182,7 MW
3,1
104 cm
375
250 MW
95 am
Transcribed Image Text:P1 + a1 2g P2 L V? +z2 + hrarbing + hg,toplam hx,sürekli=f•5•2g 2g +z + hpompa.f + az7 pg pg hk.yerel hỵ,toplam= hx,sûrekli + hxyerel Wmil Nsp 2g Протра (gH)3/4 一()-)图)第-(m)G) 1/2 mil WB (DB WA DA Wmil.B (DB (DB Wmil = pgHỳntürbin ww, p1/2(gH)5/4 PB (WB HB WB WmilA PA wa) HA Nst Wmil = prwv(V; – rw)(1 – cosß) %3D At the best efficiency point with the experiments on the A turbine DA= 72 cm, Ha= 20 m, VA = 50 m³/s, PA= 998 kg/m3, na= 205 revolution per minute, Wmila= 9 MW values have been obtained. PB= 998 kg/m3, HB= 65 m, nB= 185 A new B turbine will be designed. According to this; a) B is the volumetric flow of the turbine (VB) (m/s) find as. c) Find the specific speed of turbine B. b) Find the power of turbine B. (Wmil.B)| 2,5 285 d) Find the diameter of turbine B. 245.3 MW 35 120 cm 361 211,5 MW 2.8 156 cm 180 190 MW 2,1 144 crm 255 182,7 MW 3,1 104 cm 375 250 MW 95 am
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