Can someone help me out on number 1 and 2 and it’s also called Ideas Gas Law PV= nRTAnswer the following questions by inserting a picture ofyour work (math):1. 5.4 g of CO, are confined to a 20.0L containerat a temperature of 32.5°C. What pressuredoes the gas exert?2. Calculate the molar mass of a gas if 4.5 L of thegas at 785 torr and 23.5°C weigh 13.5g?

Answered: P V = n R T Answer the following…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Concept explainers

Question

100%

Can someone help me out on number 1 and 2 and it’s also called Ideas Gas Law

P
V
= n
R
T
Answer the following questions by inserting a picture of
your work (math):
1. 5.4 g of CO, are confined to a 20.0L container
at a temperature of 32.5°C. What pressure
does the gas exert?
2. Calculate the molar mass of a gas if 4.5 L of the
gas at 785 torr and 23.5°C weigh 13.5g?

Definition Definition Any of various laws that describe the ways in which volume, temperature, pressure, and other conditions correlate when matter is in a gaseous state. At a constant temperature, the pressure of a particular amount of gas is inversely proportional with its volume (Boyle's Law) In a closed system with constant pressure, the volume of an ideal gas is in direct relation with its temperature (Charles's Law) At a constant volume, the pressure of a gas is in direct relation to its temperature (Gay-Lussac's Law) If the volume of all gases are equal and under the a similar temperature and pressure, then they contain an equal number of molecules (Avogadro's Law) The state of a particular amount of gas can be determined by its pressure, volume and temperature (Ideal Gas law)

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions